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lorasvet [3.4K]
3 years ago
12

A moving bumper car hits the back bumper of a stationary bumper car. The momentum of the stationary car increases. Which happens

to the momentum of the moving bumper car?
-it decreases
-it stays the same
-it is converted to inertia
Physics
2 answers:
kolbaska11 [484]3 years ago
7 0
It decreases because it gave its momentum to the other car.
Romashka-Z-Leto [24]3 years ago
5 0
"It decreases" is the one among the following choices given in the question that happens to the momentum of the <span>moving bumper car. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that has actually come to your desired help.</span>
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Objects that have like charges attract each other.

Objects that have opposite charges repel each other.

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A rock falls from rest off a cliff and hits the ground in 2 seconds. If there is no air resistance, determine the rock's velocit
mihalych1998 [28]

Answer:

19.6m/s

Explanation:

A Rock falling off a cliff can be modeled as an object starting with  zero velocity moves with constant acceleration for certain period of time, for such motion following equation of motion can be used.

v(t) = v_{0} +at

here in our case v_{0} =0 because object starts off from rest and a = g =9.8m/s^2 is acceleration because of gravity ( Motion under gravity).

and of course t = 2 second.

Now by substituting all this information in equation of motion we get.

v(2s) = 0+9.8m/s^2 *2s = 19.6m/s

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.

A rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for a certain period of time, for such motion following equation of motion can be used.

here in our case  because object starts off from rest and  is acceleration because of gravity ( Motion under gravity).

and of course t = 2 seconds.

Now by substituting all this information in equation of motion we get.

V = 19.6m/s

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.

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