Answer:
The given expanded sum of the series is 
Step-by-step explanation:
Given problem can be written as
To find their sums:
Now expanding the series
That is put n=5,6,7,8,9 in the given summation
![\sum\limits_{n=5}^{9}3n+2=[3(5)+2]+[3(6)+2]+[3(7)+2]+[3(8)+2]+[3(9)+2]](https://tex.z-dn.net/?f=%5Csum%5Climits_%7Bn%3D5%7D%5E%7B9%7D3n%2B2%3D%5B3%285%29%2B2%5D%2B%5B3%286%29%2B2%5D%2B%5B3%287%29%2B2%5D%2B%5B3%288%29%2B2%5D%2B%5B3%289%29%2B2%5D)
![=[15+2]+[18+2]+[21+2]+[24+2]+[27+2]](https://tex.z-dn.net/?f=%3D%5B15%2B2%5D%2B%5B18%2B2%5D%2B%5B21%2B2%5D%2B%5B24%2B2%5D%2B%5B27%2B2%5D)
(adding the terms)
Therefore
Therefore the given sum of the series is
The given expanded sum of the series is
Slope: (y2-y1)/(x2-x1)
(-15+20)/(-18+18) = 5/0
5 cannot be divided by 0
Solution: E) undefined
Answer:
30000
Step-by-step explanation:
9×10=90
90 power 7=90[10000000]
3×10=30
30 power 3=30[1000]
900000000÷30000=30000
<span>f(x) = 3x + 3; f(33)
f(33) = 3(33) + 3
f(33) = 99 + 3
f(33) = 102</span>
