Use synthetic division to solve

Mathematics

1 answer:

Vikki [24]3 years ago

5 0

Answer:

x² + 4x + 3

Step-by-step explanation:

Dividing by (x - 5) then use h = 5 as divisor

5 | 1 - 1 - 17 - 15

↓ 5 20 15

-------------------------------

1 4 3 0 ← remainder = 0

quotient = x² + 4x + 3

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Answer:

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Step-by-step explanation:

Because Mikey weighs 15 pounds more, just add 95 pounds and 15 pounds to get Mikey's weight:

95 + 15 = 110

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$\bf ~~~~~~ \textit{Simple Interest Earned Amount}
\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$2555\\
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\end{cases}
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3 years ago

A gumball is approximately spherical and has a diameter of 1 inch. What is the approximate volume of the gumball? A gumball is a

KatRina [158]

The approximate volume of the spherical gumball is: C. 0.5236 in.³.

<h3>How to Determine the Volume of a Spherical Shape?</h3>

If a shape is spherical, it means it has a shape of a sphere. To determine the volume of the spherical shape, we would use the formula for the volume of a sphere, which is given as:

Volume of a sphere = 4/3 × π × r³, where r (radius of the sphere) is half of the diameter of the sphere.

Given the following parameters of the sphere as:

Diameter of sphere = 1 inch.

Radius (r) = 1/2(1) = 0.5 inch.

π = 3.14

To find the approximate volume of the spherical gumball, substitute the value of r into 4/3 × π × r³:

Volume of the spherical gumball = 4/3 × 3.14 × 0.5³

Volume of the spherical gumball = 4/3 × 3.14 × 0.125

Volume of the spherical gumball = (4 × 3.14 × 0.125)/3

Volume of the spherical gumball = (1.57)/3

Volume of the spherical gumball = 0.523 in.³

Therefore, we can conclude that the approximate volume of the spherical gumball is: C. 0.5236 in.³.