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andrezito [222]
3 years ago
10

Use synthetic division to solve

Mathematics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

x² + 4x + 3

Step-by-step explanation:

Dividing by (x - 5) then use h = 5 as divisor

5 | 1    - 1    - 17    - 15

    ↓     5     20     15

   -------------------------------

     1     4      3       0 ← remainder = 0

quotient = x² + 4x + 3

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A $12 beach towel is discounted 40%. Find the sales price.<br><br><br>​
Gemiola [76]

Answer:

$7.20

Step-by-step explanation:

4 0
3 years ago
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Ments
maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

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8 0
2 years ago
A basketball with a radius of 24.1 cm rolls 8.0m in 11 seconds. what is the angular frequency of the ball?
Dominik [7]
The formula for angular frequency is:

ω = velocity/radius

Since we are given distance(8.0m) and time(11 seconds) , we can also express the formula as:

ω = distance/(radius)(time)

Substituting the given values:

8.0m/(0.241m)(11s)

Which would give us the answer of 3.03 seconds.

Hope this answer helps.
8 0
3 years ago
Refer to the table below if needed.
elena-14-01-66 [18.8K]

A quadrant is the area that is divided into the x and y axes

The quadrants in which tan \theta and cot \theta are positive are I and III

<h3>How to determine the quadrants</h3>

The tangent of an angle is calculated as:

\tan(\theta) = \frac{sin(\theta)}{\cos(\theta)}

While the cotangent of the angle is calculated as:

\cot(\theta) = \frac{cos(\theta)}{\sin(\theta)}

The above equations mean that:

For the tangent and cotangent of an angle to be positive, then the sine and the cosine of the angle must have the same sign.

  • In the first quadrant, the sine and the cosine angles are positive.
  • In the third quadrant, the sine and the cosine angles are negative.

Hence, the quadrants in which tan \theta and cot \theta are positive are I and III

Read more about trigonometry ratios at:

brainly.com/question/8120556

7 0
3 years ago
3 to the power of 2 + 4 to the power of 2
julia-pushkina [17]

Answer:

25

Step-by-step explanation:

hope this helps

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3 years ago
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