All categories

3 years ago

Both and can be classified as pure substances because they have distinct properties and composition.

Chemistry

1 answer:

musickatia [10]3 years ago

4 0

Answer:

Both elements and compounds can be classifies as pure substances because they have distinct properties and composition.

Explanation:

Elements and compounds are considered as pure substances because both are always formed form are have same kind of atoms.

For example,

Carbon dioxide is compound. It always consist of one carbon atom and two oxygen atoms.

Water is compound it always have same kind of atoms two hydrogen and one oxygen that's why compounds are considered as pure substances.

Same is the case with elements. For example,

Hydrogen is element and it always consist of H atoms.

Iron is another element and it always have iron atoms.

So elements and compounds are always consist of same substances that's why they are considered as pure.

You might be interested in

Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H2S(g) 3O2(g)2H2O(l) 2SO2

Marizza181 [45]

Answer:

$\Delta _rH=-1124.14kJ/mol$

Explanation:

Hello!

In this case, since the standard enthalpy change for a chemical reaction is stood for the enthalpy of reaction, for the given reaction:

$2H_2S(g) +3O_2(g)\rightarrow 2H_2O(l) +2SO_2(g)$

We set up the enthalpy of reaction considering the enthalpy of formation of each species in the reaction at the specified phase and the stoichiometric coefficient:

$\Delta _rH=2\Delta _fH_{H_2O,liq}+2\Delta _fH_{SO_2,gas}-2\Delta _fH_{H_2S,gas}-3\Delta _fH_{O_2,gas}$

In such a way, by using the NIST database, we find that:

$\Delta _fH_{H_2O, liq}=-285.83kJ/mol\\\\\Delta _fH_{SO_2, gas}=-296.84kJ/mol\\\\\Delta _fH_{O_2,gas}=0kJ/mol\\\\\Delta _fH_{H_2S,gas}=-20.50kJ/mol$

Thus, we plug in the enthalpies of formation to obtain:

$\Delta _rH=2(-285.73kJ/mol)+2(-296.84kJ/mol)-2(-20.50kJ/mol)-3(0kJ/mol)\\\\\Delta _rH=-1124.14kJ/mol$

Best regards!

8 0

3 years ago

An unknown element sample has 2 isotopes present. The first isotope has a mass of 6.017 amu and is

oksano4ka [1.4K]

Answer:

Calculating Atomic Mass

Change each percent abundance into decimal form by dividing by 100. Multiply this value by the atomic mass of that isotope. Add together for each isotope to get the average atomic mass.

Explanation:

have a nice day

8 0

2 years ago

The maximum oxygen uptake is known as the __________.

andrezito [222]

The maximum oxygen uptake is known as the VO2 max.

4 0

3 years ago

Read 2 more answers

I need the answers to this and to see if what I put is right so far

klemol [59]

1) B+3 is ok. The exercise already put B+3. What

-------------------------------------------------------------------------------------------------------------------

2) Ge is a neutral atom because it doesn't have any charge.

Germanium has 32 electrons and 32 protons because its atomic number is 32.

Be careful with that.

Neutral atoms have the same numbers of electrons and protons.

-------------------------------------------------------------------------------------------------------------------

5 0

1 year ago

Magnesium has three naturally occurring isotopes(Mg-24, Mg-25, and Mg-26). The atomic mass and natural abundance of Mg-24 are 23

xxMikexx [17]

Answer:

The answer to your question is below

Explanation:

Data

Atomic mass Abundance

Mg -24 = 23.9850 79%

Mg -25 = 24.9858 10%

Mg - 26= ? ?

Process

1.- Find the abundance of Mg-26

The sum of the abundance of the three isotopes equals 100%

Abundance Mg-24 + Abundance-Mg-25 + Abundance-26 = 100

79 + 10 + Abundance-26 = 100

Abundance Mg-26 = 100 -89

Abundance Mg-26 = 11%

2.- Find the atomic mass of Mg-26, the average atomic mass is 24.31 amu

Average atomic mass = (abundance)(atomic mass- 24) + (abundance)

(atomic mass-25) + (abundance)(atomic mass-26)

24.31 = (0.79)(23.9850)+ (0.10)(24.9858) + (Atomic mass-26)(0.11)

24.31 = 18.94815 + 2.4986 + 0.11(atomic mass-26)

24.31 = 21.4342 + 0.11(atomic mass- 26)

0.11(atomic mass-26) = 24.31 - 21.4342

0.11(atomic mass-26) = 2.8758

Atomic mass-26 = 2.8758/0.11

Atomic mass-26 = 26.1436 amu

8 0

3 years ago

Read 2 more answers

Both __________ and __________ can be classified as pure substances because they have distinct properties and composition.

Both and can be classified as pure substances because they have distinct properties and composition.