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Answer : S=1.34 KJ
The complete question is -
<span>When 0.7521 g of benzoic was burned in a calorimeter containing 1000 g of water, a temperature rise of 3.60C was observed. What is the heat capacity of the bomb calorimeter, excluding water? The specific heat of water is 4.184 J/g-C and the heat of combustion of benzoic acid is 26.42 kJ/g.
</span>
On using the formula of
, where m is mass of benzoic acid and S is specific heat and t is temperature, we ignore S at this stage.
on solving we get,
= 0.7521 X 26.42 = 19.870 KJ
We know, =
+ 
Sp. heat of water is 4.184 J,
Here = 1000 X 4.184 X 3.6 = 15062.4 J
on multiplying X 1000 to convert into J = <span>19870.42 J
on substituting the values we get, </span>19870.482 = 15062.4 +,
hence,= <span>4808.082,
</span>Substituting in , we get, 4808.082=St ...(ignoring mass as we changed it to J)
t = 3.6, hence we get, S=1335 J/C on dividing by 1000 we get, S=1.34 KJ
The complete question is -
<span>When 0.7521 g of benzoic was burned in a calorimeter containing 1000 g of water, a temperature rise of 3.60C was observed. What is the heat capacity of the bomb calorimeter, excluding water? The specific heat of water is 4.184 J/g-C and the heat of combustion of benzoic acid is 26.42 kJ/g.
</span>
On using the formula of
on solving we get,
We know,
Sp. heat of water is 4.184 J,
Here
on multiplying
on substituting the values we get, </span>19870.482 = 15062.4 +
hence,
</span>Substituting in
t = 3.6, hence we get, S=1335 J/C on dividing by 1000 we get, S=1.34 KJ