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What is the angular displacement of the second hand on a clock after 59 seconds?

DerKrebs [107]

Answer:

a. -6.17 rad

Explanation:

60 seconds is 2π radians. Writing a proportion:

2π / 60 = x / 59

x = 6.17

The displacement is negative because the second hand moves clockwise.

6 0

3 years ago

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What would be the resulting condition if Earth's axis was perpendicular to the Sun?

blagie [28]

Answer:

I belive it would be B or D, but B seems more likely

Explanation:

3 0

3 years ago

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A deuteron consists of one proton and one neutron. A deuteron moving horizontally enters a uniform, vertical magnetic field of 0

Helen [10]

Answer:

Explanation:

Let the velocity of deuteron be v then force on it in magnetic field

Bqv , B is magnetic field and q is charge on deuteron . This force will provide centripetal force for circular path so

mv² / r = Bqv m is mass of deuteron and r is radius of circular path

v = Bqr / m

(.5 x 1.6 x 10⁻¹⁹ x 55.6 x 10⁻² )/ 3.34 x 10⁻²⁷

= 13.31 x 10⁶ m /s

6 0

3 years ago

. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu

mrs_skeptik [129]

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

2. When these photons are emitted, they travel between two reflective

surfaces to form the wave that is represented in the simulation.

3. This wave is the summation of all the photons being introduced with

every oscillation, and as they continue to travel, the amplitude

increases. 

4. This occurs because the photons are emitted in a coherent fashion;

however, amplitude when the photons overlap in an incoherent

fashion.

5. In a laser device, a small portion of photons are permitted to escape

(for use in an application). This is emulated in the simulation, by

settling the Damping to Lots such that amplitude remains relatively

constant when compared to damping of None. (Damping

represents the Loss of photons.

6. The generation of multiple wavelengths is possible in some laser

producing systems, and the diffraction angle can be varied to allow

the isolation of different wavelengths.

7. Finally, when the power of a laser is described, the wave property

that is being referenced is a function of its frequency and

amplitude.

Therefore, we can conclude that we've fully understood the concept of emission of photons and wavelength in a laser apparatus.

Learn more about wavelength here:

brainly.com/question/23023103?referrer=searchResults

5 0

3 years ago

ASTM A229 oil-tempered carbon steel is used for a helical coil spring. The spring is wound with D = 50 mm d = 10.0 mm, and a pit

horrorfan [7]

Answer

given,

D = 50 mm = 0.05 m

d = 10 mm = 0.01 m

Force to compress the spring

$F = \dfrac{d^4G\delta}{8D^3N}$

$\dfrac{\delta}{N} = p - d = 14 - 10 = 4 mm$

$F = \dfrac{d^4G}{8D^3}\times 0.004$

$F = \dfrac{0.1^4\times 79\times 10^9}{8\times 0.05^3}\times 0.004$

F = 3160 N

stress correction factor from stress correction curve is equal to 1.1

now, calculation of corrected stress

$\tau = \dfrac{8FDk_s}{\pi d^3}$

$\tau = \dfrac{8\times 3160 \times 0.05 \times 1.1}{\pi \times 0.01^3}$

= 442.6 Mpa

The tensile strength of the steel material of ASTM A229 is equal to 1300 Mpa

now,

$\tau_s \leq 0.45 S_u$

$\tau_s \leq 0.45 \times 1300$

$\tau_s \leq 585\ Mpa$

since corrected stress is less than the $\tau_s$

hence, spring will return to its original shape.

6 0

3 years ago

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