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Xelga [282]
3 years ago
15

*asap* Explain how waves, energy and matter are related.

Physics
2 answers:
shepuryov [24]3 years ago
6 0
<span>Waves are rhythmic disturbances that carry energy without carrying matter.

</span>
alexandr1967 [171]3 years ago
4 0
They are related because they are all important elements in physical science. They all deal with motion and the movement of molecules ( also volume).

Please vote my answer brainliest. thanks!
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Hi can someone pls answer the question number 2 pls i srsly need it. thank u :) ​
Anvisha [2.4K]

<em>The distance between the image and its leans is 19.04 cm...</em>

  • <u>Refer</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>attachment</u><u> </u><u>for</u><u> </u><u>detailed</u><u> </u><u>solution</u><u>!</u><u>!</u><u>~</u>

5 0
2 years ago
Read 2 more answers
Two molecules of lithium are combined with 225 grams of bromine to form two molecules of lithium bromide. If you end up with 690
4vir4ik [10]

The amount of Li present to start the reaction is 55.18g

<u>Explanation:</u>

2Li + Br₂ → 2LiBr

Molecular weight of Br₂ = 159.808 g/mol

Mass of Br₂ present = 225 g

Moles of Br₂ present during the reaction = 225 / 159.808

                                                                m = 1.4

Molecular weight of LiBr = 86.845 g/mol

Mass of LiBr formed = 690 g

moles of LiBr produced = 690 / 86.845

                               m(LiBr) = 7.95

According to the balanced equation, 2 molecules of Li reacts to for 2 molecule of LiBr

So, 7.95 moles of LiBr would require 7.95 moles of Li

The molecular weight of Li is 6.941 g/mol

Thus, the amount of lithium present to start the reaction is

moles = \frac{given weight}{molecular weight} \\\\7.95 = \frac{w}{6.941} \\\\w = 55.18g

Therefore, the amount of Li present to start the reaction is 55.18g

6 0
3 years ago
would the phases of the moon be affected if the moon didn't make one rotation for each revolution of earth?
Aleks [24]

As long as the moon orbits the Earth in the same way, the phases will be the same.

4 0
3 years ago
A 0.5kg ball of clay originally moving at 6 m/s strikes a wall and comes to rest in 0.25s, what is the magnitude of the impulse
Alex787 [66]

Answer:

C I did USA testprep

Explanation:

5 0
3 years ago
Place the single weight with a known mass on the spring and release it. Eventually, the weight will come to rest at an equilibri
aliya0001 [1]

Answer:

X=m*g/K

Explanation:

Since the elastic force of the spring is balancing the force of gravity:

Fe = m*g

Now, on the spring by Hook's law, the magnitude of the elastic force will be:

Fe = K*X     where K is the elastic constant of the spring and X is the distance the spring is strectches measured from its original lenght to its current length.

Replacing this value:

K*X = m*g   Solving for X:

X = m*g/K    This value is directly proportional to the object's weight and inversely proportional to the spring's constant.

3 0
4 years ago
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