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2 years ago

Hi can someone pls answer the question number 2 pls i srsly need it. thank u :)

Physics

2 answers:

Anvisha [2.4K]2 years ago

5 0

The distance between the image and its leans is 19.04 cm...

Refer to the attachment for detailed solution!!~

ad-work [718]2 years ago

3 0

Answer:1,0.95cm

2,21.82cms

3, 2.73

Explanation:

1,Its equation is following: 1o + 1i = 1f

1i = 1f - 1o

1i = 1−11 - 125

i = -7.64 cm - the image distance from the lens. The negative sign means that the image virtuali

h = 3.1* 7.6425 = 0.95 cm - the diameter of the coin’s imageimage

2,Use the lens equation to determine the image distance: 1/25 = 1/80 + 1/Di →

Di = 36.36 cm.

The image is real and on the opposite side of the lens as compared to the object.

The distance between object and image then is: 80 + 36.36 = 116.36 cm.

3,1/V+1/U =1/F ; 1/V =1/F-1/U ;- 1/15–1/48 =16-5/ 240 = 11/240 ; V =240/11

=21.82 CMS

IMAGE MAGNIFICATION V /U =21.82/48= 0.0.4546INVERTED

6 * 0.4546=2.7276 ≈2.73

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Acceleration = (change in speed) / (time for the change)

-- during the first second, the object increases its speed to

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3 years ago

The net external force on the propeller of a 3.0 kg model airplane is 6.8 N forward.What is the acceleration of the airplane? An

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The correct answer to the question is 2.27 $m/s^2$ i.e the acceleration of the body is 2.27 $m/s^2$ along the forward direction.

CALCULATION:

As per the question, the net external force on the propeller of model airplane F = 6.8 N.

The mass of the model air plane m = 3.0 kg

We are asked to calculate the acceleration of the air plane.

From Newton's second law of motion, we know that the net external force acting on a body is equal to the product of mass with acceleration of that body.

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⇒ $a=\ \frac{F}{m}$

$=\ \frac{6.8\ N}{3.0\ kg}$

$=\ 2.27\ m/s^2$ [ans]

The direction of acceleration is along the direction of force. Hence, the acceleration of the propeller is 2.27 $m/s^2$ along forward direction.

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4 years ago

Notice that all the initial spring potential energy was transformed into gravitational potential energy. If you compressed the s

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The question doesn't provide enough data to be solved, but I'm assuming some magnitudes to help you to solve your own problem

Answer:

The maximum height is 0.10 meters

Explanation:

Energy Transformation

It's referred to as the change of one energy from one form to another or others. If we compress a spring and then release it with an object being launched on top of it, all the spring (elastic) potential energy is transformed into kinetic and gravitational energies. When the object stops in the air, all the initial energy is now gravitational potential energy.

If a spring of constant K is compressed a distance x, its potential energy is

$\displaystyle P_E=\frac{Kx^2}{2}$

When the launched object (mass m) reaches its max height h, all that energy is now gravitational, which is computed as

$U=mgh$

We have then,

$U=P_E$

$\displaystyle mgh=\frac{Kx^2}{2}$

Solving for h

$\displaystyle h=\frac{Kx^2}{2mg}$

We have little data to work on the problem, so we'll assume some values to answer the question and help to solve the problem at hand

Let's say: x=0.2 m (given), K=100 N/m, m=2 kg

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8 0

3 years ago

You wish to lift a 400 lb car engine a vertical distance of 3 ft using a strong rope. Unfortunately, your hand crank winch can o

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Answer:

Explanation:

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Mechanical Advantage = 1200 / 100

MA = 12

7 0

4 years ago

a crane lifts four pallets of bricks each of which weigh 5000 N. the crane lifts each pallet a height of 30m. the crane takes 4

love history [14]

Answer:

625 W

Explanation:

Applying

P = W/t.................... Equation 1

Where p = power, W = Work, t = time

But,

W = Force (F) × distance (d)

W = Fd........................ Equation 2

Substitute equation 2 into equation 1

P = Fd/t.................... Equation 3

From the question,

Given: F = 5000 N, d = 30 m, t = 4 munites = (4×60) seconds = 240 seconds

Substitute these values into equation 3

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P = 625 Watt

3 0

3 years ago

Hi can someone pls answer the question number 2 pls i srsly need it. thank u :) ​

Hi can someone pls answer the question number 2 pls i srsly need it. thank u :)