1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ostrovityanka [42]
4 years ago
9

What does it mean for a strong base to be in equilibrium

Chemistry
1 answer:
bonufazy [111]4 years ago
8 0
The position of equilibrium lies far to the right, with products being favored.
You might be interested in
Explain how the climate in a specific region differs during El Niño and La Niña. Please answer in your own words.
solmaris [256]

Answer:girl and boy

Explanation:

7 0
4 years ago
(c)
serg [7]

Answer:

Substance E does not conduct electricity in both solid and molten states because of very low melting and boiling points.

In both solid and molten state free electrons are required to conduct electricity. substance E has low boiling and melting point which means substance will have relatively weak bonds. Because of weak bonds substance E might not have much free electron in its outermost shell that can cause the electric current by their coordinated movement.

Hence, substance E is unable to conduct in both melting and molten state.

3 0
3 years ago
QUESTION 24<br> Calculate [H 30+] of a solution with a pH of 2.14.
sleet_krkn [62]

Answer:

The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH).

I hope what I just explained is enough .

7 0
3 years ago
Which statement about mixtures and solutions is incorrect?
harkovskaia [24]
B)all  solutions are mixtures

5 0
4 years ago
Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 × 10-13.
lesya692 [45]

Answer:

Molar solubility of AgBr = 51.33 × 10⁻¹³

Explanation:

Given:

Amount of NaBr = 0.150 M

Ksp (AgBr) = 7.7 × 10⁻¹³

Find:

Molar solubility of AgBr

Computation:

Molar solubility of AgBr = Ksp (AgBr) / Amount of NaBr

Molar solubility of AgBr = 7.7 × 10⁻¹³ / 0.150

Molar solubility of AgBr = 51.33 × 10⁻¹³

5 0
3 years ago
Other questions:
  • How test berween nitric and sulferic acid?
    10·1 answer
  • Table sugar completely dissolved in water is an example of a?
    15·2 answers
  • Which of the following agencies provide research funding that is not federally financed? A. Department of Energy B. National Ins
    10·1 answer
  • All atoms of the same element have the same ____.
    6·2 answers
  • Draw the ester formed by the reaction of heptanoic acid and ethanol.
    9·1 answer
  • How many hydrogen atoms are in the following molecule of ammonium sulfide?<br><br> (NH4)2S
    13·2 answers
  • (50 points!) This diagram is a model of the fluorine atom.
    9·1 answer
  • What is it that lives if it is fed, and dies if you give it a drink
    13·2 answers
  • Based on Newton's third law and the force represented by the arrow, what is the reaction force in this scenario
    8·1 answer
  • [80 POINTS] Which reaction will most likely take place based on the activity series?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!