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andrezito [222]
3 years ago
12

A square has side length represented by X +4 inches write an expression to represent the area. Express your answer as a trinomia

l.
Mathematics
1 answer:
romanna [79]3 years ago
7 0

Answer:

A=(x^2+16+8x)\ \text{inches}^2

Step-by-step explanation:

Given that,

The side length of a square, l = (x+4) inches

We need to find an expression to represent the area of the square.

The area of a square is given by :

A=\text{side}^2

So,

A=(x+4)^2\\\\A=(x^2+16+8x)\ \text{inches}^2

So, the area of the square is (x^2+16+8x)\ \text{inches}^2.

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What's the answer........................
wariber [46]

Using the general recursive formula, he 25-th term in the arithmetic sequence is 29.7

<h3>How to find the value of a₂₅?</h3>

Here we have an arithmetic sequence with the first term a₁ = 3.3 and the common difference is d = 1.1

Remember that the general arithmetic recursive formula is:

aₙ = a₁ + (n - 1)*d

This formula allows us to find the n-th term of the arithmetic sequence only using the first term and the common difference.

In this case, we just need to replace n by 25 and the values written above.

a₂₅ = 3.3 + (25 - 1)*1.1 = 29.7

We can conclude that the 25th term in the sequence is 29.7

If you want to learn more about arithmetic sequences:

brainly.com/question/6561461

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5 0
2 years ago
Can someone help me plz?
ra1l [238]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Can someone please help help with this question!
Mama L [17]

Answer:

6 x 8 = 48

Step-by-step explanation:

An educated guess.

3 0
3 years ago
Read 2 more answers
If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f
nikklg [1K]

The quadratic function given by:


f(x)=a(x-h)^2+k, \ \ \ a\neq 0


is in vertex form. The graph of f is a parabola whose axis is the vertical line x=h and whose vertex is the point (h, k). So:


To translate the graph of a function to the right, left, upward or downward we have:

For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)


By knowing this things, we can solve our problem as follows:


FIRST.

  • Translating <em>11 units to the left:</em>

g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2


  • Then translating<em> 5 units down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5


Since the new function is fatter, the factor we need to multiply the term (x+11)^2 <em>must be</em> less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.


<em>Therefore, the right answer is </em><em>b. f(x) = 1/2(x + 11)^2 - 5</em>


SECOND.

  • Translating <em>8 units to the right:</em>

g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2


  • Then translating<em> 1 unit down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1


As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.


<em>Therefore, the right answer is </em><em>a. g(x) = 1/3(x - 8)^2 - 1</em>

7 0
3 years ago
Expand then simplify: 12(2p-3)
avanturin [10]

Answer:

expanding ends in the simplest form: 24p-36

Step-by-step explanation:

7 0
4 years ago
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