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frosja888 [35]
3 years ago
14

Carrie observes a blue object. Which color(s) of light does this object absorb

Physics
1 answer:
Ronch [10]3 years ago
3 0
The object carries all colors except blue.
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Particle q1 has a positive 6 µc charge. particle q2 has a positive 2 µc charge. they are located 0.1 meters apart. recall that k
Dmitrij [34]

(a) Force between the two charges

The electrostatic force between the two charges is given by:

F=k\frac{q_1 q_2}{r^2}

where k is the Coulomb's constant, q1 and q2 the two charges, r their separation.


In this problem:

q_1 =6 \mu C=6 \cdot 10^{-6}C

q_2=2 \mu C=2 \cdot 10^{-6}C

r=0.1 m


Substituting into the equation, we find

F=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(6 \cdot 10^{-6}C)(2 \cdot 10^{-6}C)}{(0.1 m)^2}=10.8 N


(b) direction of particle q2

Particle q2 wants to move in the direction of the force acting on it. The direction of the force depends on the relative sign of the two charges: like charges attract each other, opposite charges repel each other. In this case, the two charges are both positive, so they repel each other and q2 tends to move away from particle q1.

7 0
3 years ago
Read 2 more answers
Ariel's puppy weighs 15 lb. Heather's puppy weighs 50 N. Whose puppy weighs more?
yarga [219]
15 lb is nearly 6 kg amd 50 n is nearly 5 kg,so first puppy weighs more
5 0
3 years ago
Which is not a simple harmonic motion (S.H.M.) (a) Simple Pendulum (b) Projectile motion (c) None (d) Spring motion
Scrat [10]

Answer:

b) Projectile MOTION

Explanation:

SHM is periodic motion or to and fro motion of a particle about its mean position in a straight line

In this type of motion particle must be in straight line motion

So here we can say

a) Simple Pendulum : it is a straight line to and fro motion about mean position so it is a SHM

b) Projectile motion : it is a parabolic path in which object do not move to and fro about its mean position So it is not SHM

d) Spring Motion : it is a straight line to and fro motion so it is also a SHM

So correct answer will be

b) Projectile MOTION

7 0
3 years ago
In the shadow of a tree with a dense, leafy canopy, one sees a number of light spots. Surprisingly, they all appear to be circul
Bad White [126]

The characteristics of the diffraction phenomenon allow to find the result for the shape of the points of light that you pass the tree is:

  • The shape of the dots is circular because it is in the range of far-field diffraction.

Diffraction is the phenomenon where the undulatory part of the light becomes evident, it is the interference of the waves that make up each ray of light, for this phenomenon to occur it must be fulfilled that the wavelength is of the order of the space where pass the light.

In the leafy tree it has many leaves, but there are spaces between them, some of these spaces are small and it fulfills the diffraction condition, therefore we see bright spots and not a continuous shadow.

Diffraction can be classified depending on the distance to the observer:

  • Near field or fresnel. In this case the distance from the observer is small and we can see the shape of the object that creates the diffraction.
  • Far field or Fraunhoger. In this case the distance between the obstacle (leaves) and the person is great, here the information on the shape of things is lost and we have two observable forms. Lines for the case of slits and circles for the case of objects with a closed shape.

In this case, the distance from the leaves to the observer is large, therefore we are in the case of far-field diffraction and since the edge of the leaves that forms the diffraction is closed, the observable shape is a circle.

In conclusion using the characteristics of the diffraction phenomenon we can find the result for the shape of the points of light that pass the tree is:

  • The shape of the dots is circular because it is in the range of far-field diffraction.

Learn more about diffraction here:  brainly.com/question/20140459

8 0
2 years ago
The wavelength of red helium-neon laser light in air is 632.8 nm.(a) What is its frequency?(b) What is its wavelength in glass t
inn [45]

(a) 4.74 \cdot 10^{14}Hz

The frequency of a wave is given by:

f=\frac{v}{\lambda}

where

v is the wave's speed

\lambda is the wavelength

For the red laser light in this problem, we have

v=c=3\cdot 10^8 m/s (speed of light)

\lambda=632.8 nm=632.8\cdot 10^{-9} m

Substituting,

f=\frac{3\cdot 10^8 m/s}{632.8 \cdot 10^{-9} m}=4.74 \cdot 10^{14}Hz

(b) 427.6 nm

The wavelength of the wave in the glass is given by

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 = 632.8\cdot 10^{-9} m is the original wavelength of the wave in air

n = 1.48 is the refractive index of glass

Substituting into the formula,

\lambda=\frac{632.8\cdot 10^{-9}m}{1.48}=427.6\cdot 10^{-9}m=427.6 nm

(c) 2.02\cdot 10^8 m/s

The speed of the wave in the glass is given by

v=\frac{c}{n}

where

c = 3\cdot 10^8 m/s is the original speed of the wave in air

n = 1.48 is the refractive index of glass

Substituting into the formula,

v=\frac{3\cdot 10^8 m/s}{1.48}=2.02\cdot 10^8 m/s

5 0
4 years ago
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