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SVETLANKA909090 [29]
2 years ago
11

A 75.0-kg man standing on a bathroom scale in an elevator. Calculate the scale in N, reading if the elevator moves upward at a c

onstant speed of 1.5 m/s
Physics
1 answer:
Salsk061 [2.6K]2 years ago
8 0

The scale in N, reading if the elevator moves upward at a constant speed of 1.5 m/s^2 is 862.5 N.

weight of man = 75kg

speed of elevator, a = 1.5 m/ s^{2}

F - w = ma \\

F = w + ma

F = m ( a +g )

F = 75 ( 1.5 + 10 ) \\

F = 75 ( 11.5 )

F = 862.5 N

So, the scale reading in the elevator is greater than his 862.5 N weight. This indicates that the person is being propelled upward by the scale, which it must do in order to do so, with a force larger than his weight. According to what you experience in quickly accelerating or slowly moving elevators, it is obvious that the faster the elevator acceleration, the greater the scale reading.

Speed can be defines as the pace at which the position of an object changes in any direction.  Since speed simply has a direction and no magnitude, it is a scalar quantity.

Learn more about speed here:-

brainly.com/question/19127881

#SPJ4

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Sobre un recipiente lleno de agua se sumerge completamente un objeto que desplaza un volumen de 0.096 metros cúbicos de agua hac
Licemer1 [7]

Answer:

Fb = 941.76 [N]

Explanation:

La fuerza de flotacion se define como el producto de la densidad del liquido por la aceleración gravitacional y por el volumen desplazado

Fb = Ro*g*V

donde:

Fb = fuerza de flotacion [N] (unidades del Newtons)

Ro = densidad del liquido = 1000 [kg/m³]

g = aceleracion gravitacional = 9.81 [m/s²]

V = volumen desplazado = 0.096 [m³]

Reemplazando:

Fb = 1000*9.81*0.096

Fb = 941.76 [N]

7 0
3 years ago
It takes a photon 8 minutes and 25 seconds ro reach earth. What is the distance (labeled 1 au) in meter between the sun and eart
tangare [24]

Answer:

x=0.017 AU  

Explanation:

We can use the equation of speed in terms of distance. We know that the speed of light is constant value so we will have:

v=\frac{x}{t}

x=v*t

x=3*10^{8}*8.417  

x=2.53*10^{9}m  

Now we know that 1 AU = 1.496*10^{11}m

x=0.017 AU  

I hope it helps you!

3 0
3 years ago
A 3.0N force to the right acts on a 0.5kg object at rest during a time interval of 4.0 seconds .What is the velocity of the obje
monitta

Answer:

24 m/s

Explanation:

Applying Newton's second law of motion,

F = ma................ Equation 1

Where F = force acting on the object, m = mass of the object a = acceleration of the object.

First we calculate for a.

make a the subject of the formula in equation 1 above

a = F/m............... Equation 2

Given: F = 3 N, m = 0.5 kg.

Substitute into equation 2

a = 3/0.5

a = 6 m/s²

Secondly we calculate the velocity by using,

v = u+at................... Equation 3

Where v = Final velocity of the object, u = initial velocity of the object, t = time interval

Given: u = 0 m/s (at rest), a = 6 m/s², t = 4 s

Substitute into equation 3

v = 0+6(4)

v = 24 m/s

5 0
3 years ago
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A stick is a connection of two same -diameter metal rod 5 cm , and a length of both stick is 0,6m. The thermal conductivity of t
Vinil7 [7]
 (1) 12 m (2<span>) 36 m .....................</span>
8 0
4 years ago
An object travelling at 12 m/s has 64.8j of stored kinetic energy. What is the mass of the object, in grams?​
bekas [8.4K]

Answer:

So u divided 12 divided by 64.8 okay

Explanation:

and when I getc the answer that's urs answer

4 0
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