You are the pilot of a spaceship (9.1835 × 104 kg) and you enter into elliptical orbit around an uncharted planet, Rosseforp. At
periapsis (closest approach to the planet), your ship is 4.5 × 107 m above the surface of the planet; at apoapsis (most distant) it is 2.257×108 m above the surface. The mass of Rosseforp is found by your ship’s equipment to be 1.96×1025 kg, and the period of your ship’s orbit is 83.37 hours
Find the following:i. the semimajor axis of your ship’s orbit,ii. the radius of planet Rosseforp,iii. the eccentricity of your ship’s orbit,iv. the speed of your ship at perihelion and aphelion,
Find the following:i. the semimajor axis of your ship’s orbit,ii. the radius of planet Rosseforp,iii. the eccentricity of your ship’s orbit,iv. the speed of your ship at perihelion and aphelion,
1 answer:
Answer:
Check the explanation
Explanation:
The orbital period of a satellite that is given as (T) and the mean distance from the central body (R) are connected by the following equation: representing T as the satellite period, R will be represented as the average radius of orbit for the satellite (which is the distance from center of central planet)
Kindly check the attached image below to see the step by step explanation to the above question.
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Answer:
Explanation:
given
T = 3months = 7.9 × 10⁶s
orbital speed = 88 × 10³m/s
V= 2πr÷T
∴ r = (V×T) ÷ 2π
r = (88km × 7.9 × 10⁶s) ÷ 2π
r = 1.10 × 10⁸km
using kepler's 3rd law
mass of both stars = (seperation diatance)³/(orbital speed)²
M₁ + M₂ = (2r)³/(year)²
= (1.06 × 10²⁵)/(6.2×10¹³)
1.71×10¹²kg
since M₁ = M₂ =1.71×10¹²kg ÷ 2
M₁ = M₂ = 8.55×10¹¹kg
Answer:
14.8 kg
Explanation:
We are given that
We have to find the mass of the pulley.
According to question
Moment of inertia of pulley=
Where
Hence, the mass of the pulley=14.8 kg