You are the pilot of a spaceship (9.1835 × 104 kg) and you enter into elliptical orbit around an uncharted planet, Rosseforp. At
periapsis (closest approach to the planet), your ship is 4.5 × 107 m above the surface of the planet; at apoapsis (most distant) it is 2.257×108 m above the surface. The mass of Rosseforp is found by your ship’s equipment to be 1.96×1025 kg, and the period of your ship’s orbit is 83.37 hours
Find the following:i. the semimajor axis of your ship’s orbit,ii. the radius of planet Rosseforp,iii. the eccentricity of your ship’s orbit,iv. the speed of your ship at perihelion and aphelion,
Find the following:i. the semimajor axis of your ship’s orbit,ii. the radius of planet Rosseforp,iii. the eccentricity of your ship’s orbit,iv. the speed of your ship at perihelion and aphelion,
1 answer:
Answer:
Check the explanation
Explanation:
The orbital period of a satellite that is given as (T) and the mean distance from the central body (R) are connected by the following equation: representing T as the satellite period, R will be represented as the average radius of orbit for the satellite (which is the distance from center of central planet)
Kindly check the attached image below to see the step by step explanation to the above question.
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Answer:
hello your question lacks some data and required diagram
G = 77 GPa, т all = 80 MPa
answer : required diameter = 252.65 * 10-^3 m
Explanation:
Given data :
force ( P ) = 660 -N force
displacement = 15 mm
G = 77 GPa
т all = 80 MPa
i) Determine the required diameter of shaft BC
considering the vertical displacement ( looking at handle DC from free body diagram )
D' = 0.3 sin∅ , where D = 0.015
hence ∅ = 2.8659°
calculate the torque acting at angle ∅ of CD on the shaft BC
Torque = 660 * 0.3 cos∅
= 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N
hello attached is the remaining part of the solution
