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Cloud [144]
3 years ago
13

Joe rides his bicycle in a straight line for 2 hour with an average velocity of 13 km/h south, how far has he ridden?

Physics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

ans is 3.125 km

i hope this is correct

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A minibus drives with a constant speed of 76 miles per hour. How can I travel in 4 hours?
nikdorinn [45]

Answer:

Answer:

304

Explanation:Answer:

5 0
3 years ago
A diver stands on a diving platform 10.0 m above the surface of a pool and leaps upward with an initial speed of 2.5 m/s. how fa
Alexus [3.1K]
<span>The diver is heading downwards at 12 m/s Ignoring air resistance, the formula for the distance under constant acceleration is d = VT - 0.5AT^2 where V = initial velocity T = time A = acceleration (9.8 m/s^2 on Earth) In this problem, the initial velocity is 2.5 m/s and the target distance will be -7.0 m (3.0 m - 10.0 m = -7.0 m) So let's substitute the known values and solve for T d = VT - 0.5AT^2 -7 = 2.5T - 0.5*9.8T^2 -7 = 2.5T - 4.9T^2 0 = 2.5T - 4.9T^2 + 7 We now have a quadratic equation with A=-4.9, B=2.5, C=7. Using the quadratic formula, find the roots, which are -0.96705 and 1.477251164. Now the diver's velocity will be the initial velocity minus the acceleration due to gravity over the time. So V = 2.5 m/s - 9.8 m/s^2 * 1.477251164 s V = 2.5 m/s - 14.47706141 m/s V = -11.97706141 m/s So the diver is going down at a velocity of 11.98 m/s Now the negative root of -0.967047083 is how much earlier the diver would have had to jump at the location of the diving board. And for grins, let's compute how fast he would have had to jump to end up at the same point. V = 2.5 m/s - 9.8 m/s^2 * (-0.967047083 s) V = 2.5 m/s - (-9.477061409 m/s) V = 2.5 m/s + 9.477061409 m/s V = 11.97706141 m/s And you get the exact same velocity, except it's the opposite sign. In any case, the result needs to be rounded to 2 significant figures which is -12 m/s</span>
7 0
3 years ago
what would happen when an inflated balloon is place in an ice bath and the atmosphere pressure has not changed?
ruslelena [56]

The inflated balloon shrinks when it is placed in an ice bath with no change in atmospheric pressure.  

<u>Explanation:</u>

        When the inflated balloon is subjected to an ice bath, it shrinks. This is due to the fact that smaller volume gets occupied by the air/gas inside the balloon as the temperature decreases. Hence, causes the balloon walls to collapse.  

         An ice bath also lowers the overall air temperature of the balloon inside. As the temperature decreases, the air molecules move more slowly and with lower energy. Because of the particle's lower energy, their collisions with the walls are not enough to keep the inflated balloon.

7 0
3 years ago
Both Josef Loschmidt and Amedeo Avogadro contributed to our understanding of basic molecular numbers, sizes, and reaction ratios
lbvjy [14]

The  Avogadro’s number is used to represent the number of elementary entities that exist in one mole of a compound.

<h3>What is the  Avogadro’s number?</h3>

The  Avogadro’s number is used to represent the number of elementary entities that exist in one mole of a compound. The numerical value of the  Avogadro’s number is obtained as 6.02 x 10^23 and consists of the atoms, molecules and ions in the compound.

The scientist Josef Loschmidt strengthened the  Avogadro’s number  by  obtaining the number of particles in one cubic centimeter of gas under standard conditions.

Learn more about Avogadro's number:brainly.com/question/11907018

#SPJ1

5 0
2 years ago
In a device like the one shown below, the cylinder is allowed to fall a distance of 300 m. As a result, the temperature of the w
Delvig [45]

Answer:

Increase in the temperature of water would be 0.9 degree C

Explanation:

As we know by energy conservation

Change in the gravitational potential energy of the cylinder = increase in the thermal energy of the water

Here we know that the gravitational potential energy of the cylinder is given as

U = mgh

here we have

h = 300 m

now we can say

Mc\Delta T = (m \times 9.8 \times 300)

now if the cylinder falls from height h = 100 m

then we have

Mc\Delta T' = (m \times 9.8 \times 100)

now from above two equations

\frac{\Delta T'}{\Delta T} = \frac{100}{300}

\Delta T' = 2.7 \times \frac{1}{3} = 0.9 Degree C

8 0
3 years ago
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