Since the angle is West of North, therefore to find for
the westward component (horizontal component) of the vector, we use the sin
function:
sin θ = opposite side / hypotenuse = westward component /
resultant vector
So the westward component (x) is:
x = 85.42 sin 23
<span>x = 33.38 unit</span>
R = 1.4GΩ.
The relation between the resistance and the resistivity is given by the equation R = ρL/A, where ρ is the resistivity of a given material, L is the length and A is the cross-sectional area of the material.
To calculate the resistance of a wire of L = 2m, ρ = 49x10⁴Ω.m and A = 0.7mm² = 0.7x10⁻³m² we have to use the equation R = ρL/A.
R = [(49x10⁴Ω.m)(2m)/0.7x10⁻³m²
R = 98x10⁴Ω.m²/0.7x10⁻³m²
R = 1.4x10⁹Ω = 1.4GΩ
When the oscillator is at maximum extension, we know all of its energy is in Potential Energy, so if the total oscillation energy is 4.1 J, we know that at maximum displacement of 0.2 m, that
<span>energy = 1/2 kA^2 where A= 0.2 m </span>
<span>k= 2E / A^2 = 2*4.1 J /0.2^2=200 N/m </span>
<span>the frequency of oscillation is (1/2pi) sqrt[k/m] </span>
<span>knowing k and m, we can substitute values and find frequency</span>
