Answer:
i think the answer is D.
Explanation:
for the chemical equation in all the other answers are true so therefor d is not.
Assuming that 2H2O(l) is the product, the reactants would be 2H2(g) and O2(g). The number of moles in the reactants would be 2 moles of H2 and 1 mole of O2.
Upon a constant pressure (P), volume (V) of a gas will vary in direct proportion to changes in temperature (T). So V1/T1 = V2/T2
V2 = V1T2/T1 = (500)(300)/150
V2 = 150000/150 = 1000 mL
Answer:
The number of chlorine atoms present in
units of gold III chloride is
Explanation:
Formula of Gold (III) chloride: 
<em>Avogadro Number</em> : Number of particles present in <u>one mole</u><u> </u>of a substance.
Using,


= 1 mole(0.9999 , nearly equal to 1 )
The given Gold III chloride sample is 1 mole in amount.
= 1 mole of 
In this Sample,
1 mole of
will give = 3 mole of Chlorine atoms
1 mole of Cl contain =
3 mole of Cl contain = 
3 mole of Cl contain =
So,
The number of chlorine atoms present in
units of gold III chloride is
Mixing all these would create sodium hydrogen carbonate (baking soda)