Hi there!
According to Newton's second law:
∑F = m · a, where:
∑F = net force (N = kgm/s²)
m = mass (kg)
a = acceleration (m/s²)
Rearrange to solve for acceleration:
F/m = a
20N / 4.0kg = 5 m/s²
Answer:c
Explanation:
Given
object is falling Freely with an odometer
Suppose it falls with zero initial velocity
so distance fallen in time t is given by

here u=0 and t=time taken

for 

for 

distance traveled in 2 nd sec
for 

distance traveled in 3 rd sec
so we can see that distance traveled in each successive second is increasing
Answer: a
Explanation: because the answer is 1.4444444 and that's the closest
We can use the kinematic equation

where Vf is what we are looking for
Vi is 0 since we start from rest
a is acceleration
and d is the distance
we get
(Vf)^2 = (0)^2 + 2*(2)*(500)
(Vf)^2 = 2000
Vf = about 44.721
or 44.7 m/s [if you are rounding this by significant figures]