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3 years ago

Which has more electron shells: oxygen or sulfur? How do you know?

2 answers:

6 0

Oxygen is on a Period 2 Where sulfur is on a Period 3. Therefore Sulfur has more electron shells than oxygen. :) hope this somewhat helps

Sever21 [200]3 years ago

3 0

Deffinitly oxygen cause everyone breathes and yah.

You might be interested in

The work function of a metal surface is 4.80 × 10-19 J. The maximum speed of the electrons emitted from the surface is vA = 7.7

poizon [28]

Answer:

$\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=3.32344\times 10^{-7}\ m$

Explanation:

h = Planck's constant = $6.63\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

$W_0$ = Work function = $4.8\times 10^{-19}\ J$

$v_A$ = Velocity of A particle = $7.7\times 10^5\ m/s$

$v_B$ = Velocity of B particle = $5.1\times 10^5\ m/s$

The wavelength is given by

$\lambda=\frac{hc}{\frac{1}{2}mv^2+W_0}$

$\lambda_A=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(7.7\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_A=2.65177\times 10^{-7}\ m$

The wavelength $\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(5.1\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_B=3.32344\times 10^{-7}\ m$

The wavelength $\lambda_B=3.32344\times 10^{-7}\ m$

5 0

4 years ago

Near the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of

xxMikexx [17]

Answer:

a. 0.7 m/s

b. The second runner

c. 4.20 meters

Explanation:

a. To know the relative speed we can use the following equation:

Relative Speed (Vr) = V1 - V2

The relative speed is used to compared the velocity of one object (V1) to another object (V2). To learn the Relative Velocity from the second runner to the first we do the following:

Relative Speed (Vr) = Second Runner Velocity (Vs) - First Runner Velocity (Vf)

Vr = 4.20 m/s - 3.50 m/s

Vr = 0.7 m/s

This means that the second runner is gaining 0.7 meter from the first runner each second.

b. To know which runner will gain the race, we need to keep in mind, that the seconds runner is 45 meter more away that the first runner from the goal. Knowing this, the winner will be the one that reach the goal on less time.

Because movement is constant, we can use the following equation:

Velocity (V) = Distance (D) / Time (T)

To get the time we do:

T = D / V

Now, for the first runner:

T = 250 meters / (3.50 m/s)

T = 71.42 seconds

For the second runner.

T = (250 meters + 45 meters) / (4.20 m/s)

T = 70,23 seconds

Because the second runner takes less time to reach the goal, he wins the race.

c. Because it is know how much time takes the winner to get to the finish line, we can use that same time to know how far was the first runner from the goal. This is posible we know that how far he is from the goal is as follows.

Distance from goal (Dg) = Total Distance (D) - Distance travelled (Dt)

Where Total Distance (D) is 250 mts. And the distance travelled can be obtained by using the following equation.

Velocity (V) = Distance (D) / Time (T)

Searching for distance:

D = V / T.

D = (3.50 m/s) * 70.23 s

D = 245,80 meters

Soo

Distance from goal (Dg) = Total Distance (D) - Distance travelled (Dt)

Dg = 250 meters - 245,80 meters

Dg = 4,20 meters

The first runner was 4,20 meter behind the second one when the second runner crossed the goal

3 0

4 years ago

Read 2 more answers

Two runners start simultaneously from the same point on a circular 200-m track and run in the same direction. One runs at a cons

sladkih [1.3K]

Answer

given,

length of the track = 200 m

speed of runner 1 = 6.20 m/s

speed of the runner 2 = 5.5 m/s

distance covered by the fastest runner, d = 6.2 t

distance covered by the slow runner,d = 5.50 t + 200

time taken to overtake for the first time

6.2 t = 5.50 t + 200

0.7 t = 200

t = 285.7 s

distance covered from the starting point

d = 6.2 t

d = 6.2 x 285.7

d = 1771.43 m

for next overtaking time taken will be double

t' = 258.7 x 2 = 571.4 s

distance travel by the runner from the starting point

d' = 6.2 t'

d' = 6.2 x 571.4

d' = 3542.68 m

5 0

4 years ago

In what way do emotions function like a drive?

o-na [289]

Emotions show how you feel at that exact moment.
So if i we're to drive with no traffic, it would mean that it would be a good day with no worries.
If i had major traffic driving, it would mean alot of things are happening at once and it would make me angry and frustrated.

If that is what you mean by drive, i have just explained what you need.
Please comment if you mean something else than the drive i mean.

8 0

3 years ago

A spring-loaded toy gun is used to launch a 12.0-g plastic ball. The spring which has a spring constant of 15.0 N/m is compresse

ziro4ka [17]

Answer:

the elastic potencial energy stored when the spring is compressed x=8 cm is K(x)= 0.048 J

Explanation:

since the work is related with the force through

W=∫F dx

for a spring of constant k :

F=k*x , where F= compression force, x= compression length

then for a compression from 0 until x

W=∫F dx = ∫ k*x dx = k ∫x dx =1/2*k*x² - 1/2*k*0² = V(x) - V(0)

since the work depends only on the final value of compression and not on the process 1/2*k*x² represents the elastic potential energy V stored in the spring, then

V(0) = 1/2*k*0² = 0

V(x) = 1/2*k*x²

when the spring is compressed x= 8 cm = 0.08m , the elastic potencial energy is

V (x) = 1/2*k*x² = 1/2 * 15 N/m* (0.08m)² = 0.048 J

4 0

4 years ago