Answer:
Incomplete question: 9.9 mL of 0.01 M EDTA, and 10 mL of buffer with a pH of 4.
The concentration of [HY³⁻] is 1.8x10⁻²⁸mol/L
Explanation:
Given information:
10 mL of 0.01 M VOSO₄ = 0.01 L
9.9 mL of 0.01 M EDTA = 0.0099 L
10 mL of buffer = 0.01 L
pH of 4
Question: Calculate HY³⁻, [HY³⁻] = ?
Moles of EDTA:
The concentration of Y⁴⁺:
At pH = 4 Y⁴⁻ = 3.8x10⁻⁹
mol/L
The concentration of [H₂Y²⁻]:
The reaction:
H₂Y²⁻ → H⁺ + HY³⁻
The concentration of HY³⁻
Solving for HY³⁻
[HY³⁻] = 1.8x10⁻²⁸mol/L
Answer : For the experiment to study the diffusion across the semi permeable membrane, following are the safety steps that will help to handle chemicals safety;
- Use droppers to transfer small amounts of chemicals into another glassware, it will prevent the unnecessary spillage of the chemical.
- Use tongs to move hot objects as they may cause severe burns.
- Check the test tubes for chips prior to using them otherwise it may leak the chemical inside it
- Washing your hands after you finishing the lab experiment, this will ensure that food is not contaminated while consuming, with the chemicals that were stuck on the hands.
Answer:
Atoms of matter are electrically neutral because their nuclei contain the same number of protons as there are electrons surrounding the nuclei. Electric current and charged objects involve the separation of some of the negative charge of neutral atoms.
Do 36-29 which is 7 and since 29 is before 36 it’s negative so -7