1) The mass of 1 mole of virus is
2) There are 5.6 moles of viruses in an oil tanker
Explanation:
1)
One mole of a substance is the amount of that substance containing a number of particles equal to the Avogadro number:
This means that 1 mole of this virus should contain a number of virus particles equal to .
We know that the mass of 1 virus particle is
Therefore, the mass of 1 moles of viruses is equal to the mass of a single virus particle multiplied by the number of virus particles in one mole, :
2)
In this problem, we have that the mass of the oil tanker is
We also know that the mass of one mole of virus is
Therefore, we can find how many moles of viruses have a mass equal to the mass of the oil tanker by dividing the mass of the oil tanker by the mass of 1 mole of virus particles.
Mathematically, this is done by the following operation:
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Answer:
B = b -a/RT
C = b^2
a = 1.263 atm*L^2/mol^2
b = 0.03464 L/mol
Explanation:
In the given question, we need to express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms of the parameters a and b. Therefore:
Using the van deer Waals equation of state:
With further simplification, we have:
Then, we have:
Therefore,
Using the expansion:
Therefore,
Thus:
equation (1)
Using the virial equation of state:
Thus:
equation (2)
Comparing equations (1) and (2), we have:
B = b -a/RT
C = b^2
Using the measurements on argon gave B = −21.7 cm3 mol−1 and C = 1200 cm6 mol−2 for the virial coefficients at 273 K.
[/tex] = 0.03464 L/mol
a = (b-B)*RT = (34.64+21.7)*(1L/1000cm^3)*(0.0821)*(273) = 1.263 atm*L^2/mol^2
Answer:
w = 0.00098 N
Explanation:
Given data:
Acceleration = 9.80 m/s²
Mass of honey = 0.0001 Kg
weight = ?
Solution:
Formula:
w = mg
w = weight
m = mass
g = acceleration due to gravity
Now we will put the values in formula:
w = 0.0001 Kg × 9.80 m/s²
w = 0.00098 N
I pretty sure it’s level 3
Fluorine - 18.998 u
chromium - 51.996 u
tellurium - 127.6 u
dysprosium - 162.5 u