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3 years ago

The diagram below shows a 5.00-kilogram block

Physics

2 answers:

bixtya [17]3 years ago

4 0

The name and strength of the force holding the block up is 50 N upward - Normal force.

The given parameters:

Mass of the block, m = 5 kg

The weight of the block acting downwards due to gravity is calculated as follows;

W = mg

where;

g is acceleration due to gravity = 10 m/s²

W = 5 x 10

W = 50 N (downwards)

Since the block is at rest, an a force equal to the weight of the block must be acting upwards. This force is known as normal reaction.

Fₙ = 50 N (upwards)

Thus, the name and strength of the force holding the block up is 50 N upward - Normal force.

Learn more about Normal force here: brainly.com/question/14486416

cestrela7 [59]3 years ago

4 0

The block will remain on the table because the normal force balances with the weight of the block. The correct answer is 50 N upward normal force

From the diagram shown a 5.00-kilogram block at rest on a horizontal, frictionless table. The weight of the block will act downward which will be

Weight W = mg

let g = 10 m/ $s^{2}$

W = 5 x 10

W = 50 N

The block will also produce an equal but in opposite direction of a normal force which is equal to the weight of the block. That is,

Normal force N = 50 N

The block will remain on the table because the normal force balances with the weight of the block.

Therefore, the correct name and strength of the force holding the block up is 50 N upward normal force.

Learn more about stability here: brainly.com/question/517289

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Learn more about ideal gases: brainly.com/question/26450101

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