Answer:
1. Count the atoms of each element in the reactants and the products.
2. Use coefficients; place them in front of the compounds as needed.
Explanation:
Answer:
the maximum deformation undergone by the spring = 47.46 cm
Explanation:
Using conservation of momentum:

where:




Then;




v = 19.375 m/s
However ; using conservation of energy to determine the maximum deformation undergone by the spring ; we have:
![\frac{1}{2} [m_Av_A^2 +m_Bv_B^2] =\frac{1}{2}[(m_A+m_B)v^2 + kx^2]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bm_Av_A%5E2%20%2Bm_Bv_B%5E2%5D%20%3D%5Cfrac%7B1%7D%7B2%7D%5B%28m_A%2Bm_B%29v%5E2%20%2B%20kx%5E2%5D)
![[m_Av_A^2 +m_Bv_B^2] =[(m_A+m_B)v^2 + kx^2]](https://tex.z-dn.net/?f=%5Bm_Av_A%5E2%20%2Bm_Bv_B%5E2%5D%20%3D%5B%28m_A%2Bm_B%29v%5E2%20%2B%20kx%5E2%5D)
![[\frac{250*10^3}{9.81}*40^2 + \frac{550*10^3}{9.81}*10^2] =[ (\frac{800*10^3}{9.81} )*19.375^2 + 70 *10^6 \ * x^2]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B250%2A10%5E3%7D%7B9.81%7D%2A40%5E2%20%2B%20%5Cfrac%7B550%2A10%5E3%7D%7B9.81%7D%2A10%5E2%5D%20%3D%5B%20%28%5Cfrac%7B800%2A10%5E3%7D%7B9.81%7D%20%29%2A19.375%5E2%20%2B%2070%20%2A10%5E6%20%5C%20%2A%20x%5E2%5D)
x = 0.4746 m
x = 47.46 cm
Thus, the maximum deformation undergone by the spring = 47.46 cm
Answer:
2.2 s
Explanation:
Hi!
Let's consider the origin of the coordinate system at the ground, and consider that the clam starts with zero velocity, the equation of motion of the clam is given by

We are looking for a time t for which x(t) = 0

Solving for t:

Rounding at the first decimal:
t = 2.2 s
km x h = km/h
First trial: 6 x 1 = 6km/h
Second trial: 9 x 2 = 18km/h
6 + 18 = <u>24km/h</u> (Total)
Or
6 + 9 = 15 km
2 + 1 = 3h
15 + 3 = 18
15 x 2 = 30
3 x 2 = 6
30 - 6 = <u>24km/h</u>