The question is incomplete. You dis not provide values for A and B. Here is the complete question
Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.
A = 12
B = 18
Answer:
18.5⁰
Explanation:
Angle of incidence i = 12.0 + A
A = 12
= 12.0 + 12
= 14
Refractive index u = 1.10 + B/100
= 1.10 + 18/100
= 1.10 + 0.18
= 1.28
We then find the angle of refraction index u
u = sine i / sin r
u = sine24/sinr
1.28 = sine 24 / sine r
1.28Sine r = sin24
1.28 sine r = 0.4067
Sine r = 0.4067/1.28
r = sine^-1(0.317)
r = 18.481
= 18.5⁰
Answer:
temperature on left side is 1.48 times the temperature on right
Explanation:
GIVEN DATA:
T1 = 525 K
T2 = 275 K
We know that
n and v remain same at both side. so we have
..............1
let final pressure is P and temp 
..................2
similarly
.............3
divide 2 equation by 3rd equation
![\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B11%7D%5E%7B-2%2F3%7D%20%5Cfrac%7B21%7D%7B11%7D%5E%7B5%2F3%7D%20%3D%20%5B%5Cfrac%7BT_1%20%7Bf%7D%7D%7BT_2%20%7Bf%7D%7D%5D%5E%7B5%2F3%7D)
thus, temperature on left side is 1.48 times the temperature on right
Well there are a couple ways.
1: The easiest, plant cells have a cell wall or extra protection. You will not find this on an animal cell, as there is only a membrane.
2: Chloroplast. This also will not be found in animal cells as they produce the plant's green color as well as the sugar.
Hope this helps!
Answer:
Electric field intensity is the force experienced by a test charge q in a electric field E.
Answer:
Explanation:
The 2 equations we need here are, first:
and then once we solve for the acceleration here:
Δx
Solving for acceleration:
and now we will use that in the other equation:
Δx and
36 = 16 + 
Δx and
20 = Δx and
Δx so
Δx = 50 m
