1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iVinArrow [24]
2 years ago
15

I need help to convert 23.5 million nanometers to millimeters

Engineering
2 answers:
AysviL [449]2 years ago
4 0
It is the same answer 23.5 and the reason why is because we use the formula which is divide the length value by 1e+6. The formula means 235000000. Hope this helps!
Harman [31]2 years ago
3 0

Answer: 23.5

Explanation: divide the length value by 1e+6

You might be interested in
A good rule of thumb in hazardous conditions is to _____.
Aloiza [94]

Answer:

C. Have your hazard lights on

Explanation:

Speeding up will cause an accident

Counter steering is not easy to do

Slowing down my result in you being rear ended

5 0
2 years ago
Read 2 more answers
Handsaw teeth are very sharp: to avoid being cut by the teeth, keep hands and fingers well away from the
siniylev [52]
Handsaw teeth are very sharp: to avoid being cut by the teeth, keep hands and fingers well away from the
path of the blade
6 0
2 years ago
Read 2 more answers
Many radios can be operated either by plugging them into the wall or by using batteries. How can a radio use either source of cu
ch4aika [34]

Answer:

The electric current from the batteries installed in a radio supplies direct current (DC) electricity to the radio components directly as an alternative source to the Alternating Current (AC) converted to DC by the power unit located at the radio end of the cable plugged into the wall outlet.

Explanation:

Part of the power unit in a radio includes an AC to DC converter, which is an electrical circuit that is able to convert the alternating current power input from the wall outlet into a direct current output to the radio with which the radio can work

The alternative source of electric current from the batteries installed in a radio bypasses the AC to DC converter and supplies power directly to the radio so it can also work.

5 0
3 years ago
P10.12. A certain amplifier has an open-circuit voltage gain of unity, an input resistance of and an output resistance of The si
klio [65]

complete question

A certain amplifier has an open-circuit voltage gain of unity, an input resistance of 1 \mathrm{M} \Omega1MΩ and an output resistance of 100 \Omega100Ω The signal source has an internal voltage of 5 V rms and an internal resistance of 100 \mathrm{k} \Omega.100kΩ. The load resistance is 50 \Omega.50Ω. If the signal source is connected to the amplifier input terminals and the load is connected to the output terminals, find the voltage across the load and the power delivered to the load. Next, consider connecting the load directly across the signal source without the amplifier, and again find the load voltage and power. Compare the results. What do you conclude about the usefulness of a unity-gain amplifier in delivering signal power to a load?

Answer:

3.03 V  0.184 W

2.499 mV  125*10^-9 W

Explanation:

First, apply voltage-divider principle to the input circuit: 1

V_{i}= (R_i/R_i+R_s) *V_s = 10^6/10^6+(0.1*10^6)\\*5

    = 4.545 V

The voltage produced by the voltage-controlled source is:

A_voc*V_i = 4.545 V

We can find voltage across the load, again by using voltage-divider principle:  

V_o = A_voc*V_i*(R_o/R_l+R_o)

      = 4.545*(100/100+50)

      = 3.03 V  

Now we can determine delivered power:  

P_L = V_o^2/R_L

      = 0.184 W

Apply voltage-divider principle to the circuit:  

V_o = (R_o/R_o+R_s)*V_s

       = 50/50+100*10^3*5

       = 2.499 mV

Now we can determine delivered power:  

P_l = V_o^2/R_l

     = 125*10^-9 W

Delivered power to the load is significantly higher in case when we used amplifier, so a unity gain amplifier can be useful in situation when we want to deliver more power to the load. It is the same case with the voltage, no matter that we used amplifier with voltage open-circuit gain of unity.  

4 0
3 years ago
Oxides of nitrogen contribute to the formation of?
Nat2105 [25]

Answer:

B. Acid rain.

C. Photochemical smog.

Explanation:

Oxides of nitrogen contribute to the formation of photochemical smog and acid rain. Photochemical smog is a type of smog produced when ultraviolet light from the sun reacts with nitrogen oxides in the atmosphere while on the other hand, when nitrogen oxide react with the water vapor in the atmosphere forming nitric acid which falls on the earth surface with the help of precipitation.

3 0
3 years ago
Other questions:
  • Compute L, T, M, LC, and R and stations of the BC and EC for the circular curve with the given data of: I (delta) = 22°15′00" an
    10·1 answer
  • In a diesel engine, the fuel is ignited by (a) spark (c) heat resulting from compressing air that is supplied for combustion (d)
    14·1 answer
  • The wall of drying oven is constructed by sandwiching insulation material of thermal conductivity k = 0.05 W/m°K between thin me
    8·1 answer
  • Using the technique of bitwise ANDing, find the IP address of the network # (this could be a network or subnet) on which the mac
    14·1 answer
  • A family member who hasn’t worked with computers before has decided to change jobs. You’ve been asked to explain some of the bas
    6·2 answers
  • What does polarity give you information about?
    10·1 answer
  • Explain the importance of water quality in aquaculture business.
    8·2 answers
  • John has just graduated from State University. He owes $35,000 in college loans, but he does not have a job yet. The college loa
    6·1 answer
  • A. Briefly describe the microstructural difference between spheroidite and tempered martensite. Explain why tempered martensite
    14·1 answer
  • Which of these processes uses a die and a press to form parts?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!