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yKpoI14uk [10]
3 years ago
12

What is the wavelength of light that has an energy of 8.0 x 109J​

Chemistry
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

Explanation:69

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A chemist wants to observe the following reaction:
stiv31 [10]

It take more energy to break the bonds of the reactants and less energy is given off when the product bonds are formed.

<h3>What is Energy?</h3>

Energy is defined as the ability to do work. Work is done in the breaking or formation of bonds.

The standard Enthalpy (ΔH) of water which was formed in the given reaction is negative.

ΔH= Δproduct - Δreactant

This means that the energy to break the bonds of the reactants is more.

Read more about Enthalpy here brainly.com/question/14291557

3 0
2 years ago
Rubidium is in Group I of the Periodic Table and bromine is in Group VII.
tensa zangetsu [6.8K]
The answer to this question would be C
7 0
2 years ago
20) If a single gram of sugar contains 4 Calories of energy, what is the Calorie content from a serving of cereal that
Zanzabum
Answer:
36.8
Explanation:
Because 9.2 x 4 = 36.8
8 0
2 years ago
Help pleaseeee. over dilutions in chemistry
atroni [7]

Answer:

5 L

Explanation:

We'll begin by calculating the molarity of the CaCl₂ solution. This can be obtained as follow:

Mole of CaCl₂ = 0.5 mole

Volume = 2 L

Molarity =?

Molarity = mole /Volume

Molarity = 0.5 / 2

Molarity = 0.25 M

Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:

Molarity of stock solution (M₁) = 0.25 M

Volume of stock solution (V₁) = 2 L

Molarity of diluted solution (M₂) = 0.1 M

Volume of diluted solution (V₂) =?

M₁V₁ = M₂V₂

0.25 × 2 = 0.1 × V₂

0.5 = 0.1 × V₂

Divide both side by 0.1

V₂ = 0.5 / 0.1

V₂ = 5 L

Thus the volume of the diluted solution is 5 L

5 0
2 years ago
Estimate the molar mass of a gas that effuses at 1.6 times the effusion rate of CO2
Vlada [557]
To estimate the molar mass of the gas, we use Graham's law of effusion. This relates the rates of effusion of gases with their molar mass. We calculate as follows:

r1/r2 = √(m2/m1)    

where r1 would be the effusion rate of the gas and r2 is for CO2, M1 is the molar mass of the gas and M2 would be the molar mass of CO2 (44.01 g/mol) 

r1 = 1.6r2

1.6 = √(44.01 / m1)
m1 = 17.19 g/mol
7 0
2 years ago
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