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Anton [14]
3 years ago
14

If you burn 50.6 g of hydrogen and produce 452 g of water, how much oxygen reacted?

Chemistry
1 answer:
Svetllana [295]3 years ago
4 0
Acc. to Law of Conservation of Mass
Mass of reactants=Mass of Products
Let mass of Oxygen be x.
So,
50.6+x=452
x=452-50.6
=401.4 g
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an atmosphere is considered hazardous if it contains a hazardous gas in excess of 10 percent of the hazardous material's:
svlad2 [7]

Lower flammable limit means the lowest concentration of a material that will propagate a flame.

What is hazardous atmosphere?

It is an atmosphere that may expose employees to risk of death, incapacitation, impairment of ability to self-rescue, injury, or acute illness from one or more of following causes

  • Flammable gas, vapor, or mist in excess of 10 percent of lower flammable limit (LFL)
  • Airborne combustible dust at concentration that meets or exceeds its LFL

What is lower flammable limit?

  • It means the lowest concentration of a material that will propagate a flame.
  • The LFL is usually expressed as percent by volume of material in air (or other oxidant)
  • Atmospheres with concentration of flammable vapors at or above 10 percent of lower explosive limit (LEL) are considered hazardous when located in confined spaces.
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Learn more about lower flammable limit at brainly.com/question/2456135

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6 0
1 year ago
What is the mass, in grams, of 50.0L of N2 at STP?
vodka [1.7K]

Hey there!:

Molar mass N₂ = 28.0134 g/mol

28.0134 g ------------------- 22.4 L (at STP )

mass  N₂ -------------------- 50.0 L

mass N₂ = 50.0 x 28.0134 / 22.4

mass N₂ = 1400.67 / 22.4

mass N₂ = 62.529 g

Hope this helps!

6 0
3 years ago
from the balanced equation we see that h20 is 1 to 1 mole ratio the number of moles of acid and base. What is the number of mole
forsale [732]

Answer:

0.0498 mol

Explanation:

Number of moles = concentration in mol/L × volume in L

Concentration = 1 M = 1 mol/L

Volume = 49.8 mL = 49.8/1000 = 0.0498 L

Number of moles = 1×0.0498 = 0.0498 mol

5 0
3 years ago
51.7ml at 27 Celsius and 90kpa to stp
never [62]
STP is the abbreviation of standard condition for temperature and pressure which is 273.15K temperature and 1.013× 10^5 Pa pressure. Since the pressure and temperature changes, I assume the question would ask about the result of the volume. The temperature used in ideal gas should be Kelvin, so 27 Celcius would be 300.15K.
The calculation would be
PV=T
V=T/P

V2/V1= T2*P1/T1*P2
V2/V1=273.15K*  90^10^3Pa/ 300.15K *  1.013× 10^5 Pa
V2= 0.81904 * 51.7ml
V2= 42.34ml
6 0
3 years ago
1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is
earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }

So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.

\frac{6}{80}=\frac{V_{2} }{40}

V_{2}=\frac{6*40}{80}=3 L

So, 3 L will be the final volume for the gas as per Charle's law.

4 0
3 years ago
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