The Mohs scale is for natural minerals<span>. For manufactured products other measures of hardness are better. ... There are ten </span>minerals<span> in Mohs scale, talc, gypsum, calcite, fluorite, apatite, orthoclase, quartz, topaz, corundum, and for last and</span>hardest<span>, diamond.
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Answer:
4 tabletes/dose
Explanation:
mass person = (90 Lb)×(Kg/2.20462 Lb) = 40.823 Kg body
amount of medicine = 50 mg/Kg body.day
frecuency = 2 dose/day
⇒ amount of medicine/day = (50 mg/kg body.day)×(40.823 Kg body) = 2041.168 mg/day
⇒ mg medicine/dose = (20141.168 mg/day)×(day/ 2 dose) = 1020.584 mg medicine/dose
∴ mg medicine/tablet = 250 mg medicine/tablet
⇒ # tabletes/dose = (1020.584 mg medicine/dose)×(tablet/250 mg medicine) = 4.082 tabletes/dose
⇒ # tabletes/dose ≅ 4 tabletes/dose
This is the answer hope it helps you!!
Answer:
Explanation:
Hello!
In this case, considering the given table, we are able to represent the symbolic rate law as shown below:
Thus, by using the following steps, we can find both m (BF3 order of reaction) and n (BF3 order of reaction):
- Experiment 1 and 2 for the calculation of n:
So we plug in to obtain:
So the order of reaction with respect to NH3 is 1.
- Experiment 3 and 4 for the calculation of m
So we plug in to obtain:
So the order of reaction with respect to BF3 is also 1.
Now, we can compute the rate constant by solving for it on any of the experiments there, say experiment 1:
Thus, the initial reaction rate for the 0.50M BF3 and 0.020M NH3 is:
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Answer:
A 0.001 molar solution of weak acid has a pH = 4.0,The pKa is :
B. 5
Explanation:
pH = It is negative logarithm of hydrogen ion concentration.
pH = -log([H+])
Ka = It is the dissociation constant.
pKa = -log(Ka)
<u>The acid dissociates according to the equation given below:</u>
Here , The concentration of A- and H+ will be same
So,
[H+] = [A-].....(1)
Now ,
pH = 4.0
pH = -log([H+])
4.0 = -log([H+])
- 4.0 = log([H+]) take antilog both side::"use scientific calculator"
From equation (1), [A-] =
[HA] = 0.001 M (given)
Insert the value of HA , H+ and A- in Ka
pKa = -log(Ka)
pKa = 5