CxHy + O2 --> x CO2 + y/2 H2O
Find the moles of CO2 : 18.9g / 44 g/mol = .430 mol CO2 = .430 mol of C in compound
Find the moles of H2O: 5.79g / 18 g/mol = .322 mol H2O = .166 mol of H in compound
Find the mass of C and H in the compound:
.430mol x 12 = 5.16 g C
.166mol x 1g = .166g H
When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.
Therefore it is likely that either the mass of the CO2 or the mass of H20 produced is incorrect (most likely a typo).
In any event, to find the formula, you would take the moles of C and H and convert to a whole number ratio (this is usually done by dividing both of them by the smaller value).
Although the data for the experiment was not provided, we can offer a generalized answer in that when performing an experiment to achieve absolute zero temperatures, the value will never match the exact value.
<h3 /><h3>What is absolute zero?</h3>
Absolute zero is the lower limit of temperature. It is considered the coldest possible temperature that can exist. However, any attempt to reach this temperature in a controlled environment has failed, <u>scientists do not think it is possible to recreate this </u><u>temperature</u><u>. </u>
Therefore, we can confirm that the value of the absolute zero experiments did not match the accepted value. If the hypothesis was that it would be difficult or impossible to achieve, then the data would support the hypothesis, otherwise, it would fail to do so.
In summary, absolute zero is a temperature that cannot be recreated in a lab, so the value in this experiment does not match the accepted value and there is <u>no further exploration </u>to be done on this matter.
To learn more about absolute zero visit:
brainly.com/question/79835?referrer=searchResults
No, it’s impossible to have 3 masses for one object
Explanation:
As it is given that stream A is super heated. From stream tables, we get that specific enthalpy, (
) is 3054.29 kJ/kg.
For stream B, it is saturated water at 25 degree celsius. It's 
is 2546.54 kJ/kg.
Stream C, data will be as follows.
P = 200 kPa, 
= 0.9
So, 
= 
= 504.47 + 0.9 \times 2201.7
= 2486 kJ/kg
Now, energy balance formula will be as follows.
= 
= 
= 28.16 kg/s
Hence, inflow of saturated liquid is 28.16 kg/s. According to steam table, temperature of wet steam is 
Mass flow rate of out flow is 31.16 kg/s.
D.It can not be separated by a physical change.
