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weqwewe [10]
3 years ago
9

A 2.0 kg block, initially moving at 10.0 m/s, slides 50.0 m across a sheet of ice beforecoming to rest. What is the magnitude of

the average frictional force on the block?
Physics
1 answer:
inna [77]3 years ago
8 0

Answer:

The magnitude of the average frictional force on the block is 2 N.

Explanation:

Given that.

Mass of the block, m = 2 kg

Initial velocity of the block, u = 10 m/s

Distance, d = 50 m

Finally, it stops, v = 0

Let a is the acceleration of the block. It can be calculated using third equation of motion. It can be given by :

v^2-u^2=2ad

-u^2=2ad

a=\dfrac{-u^2}{2d}\\\\a=\dfrac{-(10\ m/s)^2}{2\times 50\ m}\\\\a=-1\ m/s^2

The frictional force on the block is given by the formula as :

F = ma

F=2\ kg\times (-1)\ m/s^2\\\\F=-2\ N

|F| = 2 N

So, the magnitude of the average frictional force on the block is 2 N. Hence, this is the required solution.

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