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geniusboy [140]
3 years ago
11

A rectangle with an area of 81 cm² has a length that is 3 times the width. How long is the width of the rectangle? Round to the

nearest tenth.
Mathematics
2 answers:
iren2701 [21]3 years ago
4 0

Answer:

60.75 ≈ 60.8

Step-by-step explanation:

4u-> 81

1u -> 20.25 (width)

3u-> 60.75 (length)

LenaWriter [7]3 years ago
3 0

Answer:

W ≈ 5.2 cm

Step-by-step explanation:

Represent the length and width by L and W respectively.

Then L * W = 81 cm^2, and L = 3W.

Substituting 3W for L in the first equation, we get:

3W * W - 81 = 0, or 3W^2 - 81 = 0.

To make it easier to find the final answer, rewrite 3W^2 - 81 = 0 as

            81

W^2 = ------- = 27

              3

Then W (the width) is the positive square root of 27, or W ≈ 5.2 cm

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6 0
3 years ago
Read 2 more answers
Lesson 1 Homework
Nonamiya [84]

128

This question requires us to solve an infinite GP

As we can see the first unit is 16 wide, then 8, then 4 and so on; this can be written as  

64(1,0.5,0.25,0.125,....\infinity∞)  (64 used as 16*4 = 64 is the area of the first rectangle)

We have  S∞=a/(1-r) where a is the first term and r is the common ratio of the GP for summing an infinite GP.

here we have  

a=64  \\   r=0.5

Therefore

S∞=\frac{64}{1-0.5} \\\\=\frac{64}{0.5} \\\\=128

Learn more about GP here

brainly.com/question/16954106

#SPJ9

5 0
1 year ago
A 15m long ladder reached a window 9m high from the ground on placing it against a wall at a distance x. Find the distance of th
Ilya [14]

Answer:

12 meters

Step-by-step explanation:

Given That :

Length of ladder = 15m

Height of wall =. 9 m

Using Pythagoras rule :

Adjacent² = hypotenus² - opposite²

Adjacent² = 15² - 9²

Adjacent² = 225 - 81

Adjacent² = 144

Adjacent = sqrt(144)

Adjacent, x = 12

8 0
3 years ago
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