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On combustion of 0.2 gm of organic compound gave 0.147g of CO2, 0.12g of H2O and 74.6 ml of nitrogen gas at STP. Find emperical
1 answer:
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Answer:
See explanation and image attached
Explanation:
The IUPAC system of nomenclature enables the structure of molecules to be written seamlessly from the name of the compound. Hence it is commonly called the systematic nomenclature.
The parent chain here is propane. It is substituted at the 2- position by a methyl group and at the 3-position by 4-chlorophenyl group as we can see in the image attached to this answer.
Answer:
81.59%
Explanation:
- 4NH₃ + 5O₂ → 4NO + 6H₂O
First we <u>convert 107.50 g of NH₃ into moles</u>, using its <em>molar mass</em>:
- 107.50 g NH₃ ÷ 17 g/mol = 6.32 mol NH₃
Now we <u>calculate how many moles of NO would have been formed by the complete reaction of 6.32 moles of NH₃</u>:
- 6.32 mol NH₃ *
= 6.32 mol NO
Then we <u>convert 6.32 moles of NO to grams</u>, using its <em>molar mass</em>:
- 6.32 mol NO * 30 g/mol = 189.60 g NO
Finally we <u>calculate the percent yield</u>:
- 154.70 g / 189.60 g * 100% = 81.59%