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AnnyKZ [126]
2 years ago
13

What is the name of CF7

Chemistry
2 answers:
Varvara68 [4.7K]2 years ago
7 0
Here is the answer in the picture

Wittaler [7]2 years ago
4 0

Answer:

Formula mass in daltons of the chemical component.

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Which solution would have the lowest freezing point
Vitek1552 [10]

Answer:

Ice and water

Explanation:

4 0
3 years ago
Miguel’s family drove 357 miles on their weekend trip. Their car’s average gas mileage was 25.5 miles per gallon. How many gallo
ad-work [718]

Answer:

14 gallons

Explanation:

357 divided by 14 = 25.5 and if you check your answer 14 x 25.5 = 357 (i hope this is right)

6 0
2 years ago
Read 2 more answers
The value of Kp for the reaction NO(g) 1 1 2 O2(g) 4 NO2(g) is 1.5 3 106 at 25°C. At equilibrium, what is the ratio of PNO2 to P
expeople1 [14]

Answer : The ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

Solution :  Given,

K_p=1.5\times 10^6

p_{O_2} = 0.21 atm

The given equilibrium reaction is,

NO(g)+\frac{1}{2}O_2\rightleftharpoons NO_2(g)

The expression of K_p will be,

K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}

Now put all the given values in this expression, we get:

1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}

\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}

\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5

Therefore, the ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

5 0
3 years ago
Which of the following is true about two neutral atoms of the element gold? (1 point) The nucleus is missing in both. Each has a
klio [65]

i have the same question idk the anwser tho

5 0
2 years ago
The wavelength of a particular color of violet light is 433 nm. The energy of this wavelength of light is kJ/photon. (109 nm = 1
mash [69]

Answer:

4.59 × 10⁻³⁶ kJ/photon

Explanation:

Step 1: Given and required data

  • Wavelength of the violet light (λ): 433 nm
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s
  • Speed of light (c): 3.00 × 10⁸ m/s

Step 2: Convert "λ" to meters

We will use the conversion factor 1 m = 10⁹ nm.

433 nm × 1 m/10⁹ nm = 4.33 × 10⁷ m

Step 3: Calculate the energy (E) of the photon

We will use the Planck-Einstein's relation.

E = h × c/λ

E = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/4.33 × 10⁷ m

E = 4.59 × 10⁻³³ J = 4.59 × 10⁻³⁶ kJ

5 0
2 years ago
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