Answer:
Height of cone (h) = 14.8 in (Approx)
Step-by-step explanation:
Given:
Radius of cone (r) = 6 in
Slant height (l) = 16 in
Find:
Height of cone (h) = ?
Computation:
Height of cone (h) = √ l² - r²
Height of cone (h) = √ 16² - 6²
Height of cone (h) = √ 256 - 36
Height of cone (h) = √220
Height of cone (h) = 14.832
Height of cone (h) = 14.8 in (Approx)
Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor =
or
The z factor =
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
K:A
5:3 (before)
15:9
since the total number of stamps didn't change, the total ratio should be the same.
7:5(after)
14:10
so this means 1 unit is 10stamps.
14-10=4
4 X 10= 40
Kaye have 40 more stamps than Alberto.
Answer:

Step-by-step explanation:
Given 2 similar figures with ratio of sides = a : b, then
ratio of areas = a² : b²
Here ratio of sides = 52 : 68 = 13 : 17 ← in simplest form, thus
ratio of areas = 13² : 17² = 169 : 289 = 