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2 years ago

What can cause an increase in density that results in a deep ocean current

2 answers:

6 0

The cause of the increase in density in deep ocean current is the differences in the water, which are typically due to variations in salinity and temperature.

mrs_skeptik [129]2 years ago

5 0

The movement of plates

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If the energy carried by a wave increases, which other wave property also increases?

damaskus [11]

Answer:

The answer is wavelength

5 0

3 years ago

Which of the the following distance vs time graphs represents an object the is moving at constant non zero velocity

mario62 [17]

A graph with a horizontal line

8 0

3 years ago

Equations to use: v= λ ∙ f v=d/t

Margarita [4]

b. 460.8 m/s

Explanation:

The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is

$f=\frac{v}{2L}$

where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:

$v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s$

c. 18,000 m

Explanation:

The relationship between speed of the wave, distance travelled and time taken is

$v=\frac{d}{t}$

where

v = 6,000 m/s is the speed of the wave

d = ? is the distance travelled

t = 3 s is the time taken

Re-arranging the formula and substituting the numbers into it, we find:

$d=vt=(6,000 m/s)(3 s)=18,000 m$

3 0

3 years ago

What is its rotational inertia about the meter stick in the

Sindrei [870]

Answer:

Honestly I cant understand that so please explain it someone

Explanation:

3 0

3 years ago

What is the speed of sound at 33 °C (m/s)? For a frequency of 5 kHz, how large do you expect the wavelength to be (m)?

Vedmedyk [2.9K]

Answer:

-The speed of sound at 33°C is 362.8 m/s.

-The wavelength at a frequency at 5 kHz is 0.07256 m .

Explanation:

let v = 343 m/s be the speed of sound.

let T be the temperature.

then the speed of sound V, at 33°C is given by:

V = v + 0.6×T

= 343 + 0.6×33

= 362.8 m/s

Therefore, the speed of sound at 33°C is 362.8 m/s.

the wavelength at a frequency of f = 5kHz = 5000 Hz is given by:

λ = V/f

= (362.8)/(5000)

= 0.07256 m

Therefore, the wavelength at a frequency at 5 kHz is 0.07256 m .

7 0

3 years ago