Answer:
15.6m/s
Completed Question;
For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N= 600t^2 , where t is in seconds. If the van has a speed of 20 km/h when t = 0, determine its speed when t = 5
Explanation:
Mass m = 2500kg
Speed v1 = 20km/h = 20/3.6 m/s = 5.556 m/s
To determine speed v2;
Using the principle of momentum and impulse;
mv1 + ∫₀⁵ F dt = mv2
The distance from the base of the building the rock will land is 26.4 m
<h3>Data obtained from the question </h3>
- Horizontal velocity (u) = 20 m/s
- Height (h) = 8.50 m
- Distance (s) =?
<h3>Determination of the time to reach the ground </h3>
- Height (h) = 8.50 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) =?
h = ½gt²
8.5 = ½ × 9.8 × t²
8.5 = 4.9 × t²
Divide both side by 4.9
t² = 8.5 / 4.9
Take the square root of both side
t = √(8.5 / 4.9)
t = 1.32 s
<h3>How to determine the distance </h3>
- Horizontal velocity (u) = 20 m/s
- Time (t) = 1.32 s
- Distance (s) =?
s = ut
s = 20 × 1.32
s = 26.4 m
Learn more about motion under gravity:
brainly.com/question/22719691
Answer:
The soup still is cool, or since its recent it will take a while to get warmer
Explanation:
C = 3 uf = 3 × 10^(-6) f
v = 6volts
Q = C.v
= <span>3 × 10^(-6) </span>× 6
= 18 × 10^(-6)
= 1.8 = 10^(-5)
