I’m not sure, is there any other words you can explain it in ..?
Answer:
5 minutes
Explanation:
Let X, be the time to observe light for the 2-m
Therefore,
If it takes 4-m telescope 10 minutes
then ⇒ X × 4-m = 2-m × 10
X minutes = 20/4 = 5 minutes
time 5 minutes
A short focal length will give a wide field of view but the objects in the field of view will appear small. A longer focal length will produce a larger image and a shorter focal length will produce a smaller image. The eyepiece is then used, much like a microscope, to magnify that image.
It will take 4-m telescope more time to view because of it's larger image
Magnification
The magnification of an astronomical telescope changes with the eyepiece used. It is calculated by dividing the focal length of the telescope (usually marked on the optical tube) by the focal length of the eyepiece (both in millimeters). Thus:
TELESCOPE FOCAL LENGTH / OCULAR FOCAL LENGTH = MAGNIFICATION
For example, a telescope with a 1000mm focal length using a 10mm ocular is operating at 100x magnification (1000/10=100).
Answer:
The right answer is "18 m/s".
Explanation:
The given values are:
Velocity,
V = 6 m/s
Tension,
T = 9 N
As we know,
⇒
On substituting the given values, we get
⇒
⇒
⇒
⇒
Now,
For 81 N the velocity will be:
⇒
⇒
Answer:
The package will be directly below the location of the plane.
Explanation:
Look up projectile motion for more information. The horizontal speed of the package is separate from the vertical speed of the package. The vertical speed of the falling package will be based on the rate of acceleration and the height of the package when dropped. The horizontal speed of the package will be the same as the plane so the package will remain directly below the plane the entire time until the package hits the ground.
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