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Firdavs [7]
3 years ago
12

If m = 45g and V = 15ml, what is D in g/ml?​

Chemistry
1 answer:
ch4aika [34]3 years ago
6 0

Answer:

3 g/mL

Explanation:

We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).

Formula

D=m/v

Given data:

Mass= 45 g

Volume= 15 mL

Now we will put the values in formula:

D=45 g/ 15 mL= 3 g/mL

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Please help
ludmilkaskok [199]

Answer: The molecular formula will be C_3H_9

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

The empirical formula is CH_3

The empirical weight of CH_3 = 1(12)+3(1)= 15g.

The molecular weight = 45.0 g/mole

Now we have to calculate the molecular formula:

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{45}{15}=3

The molecular formula will be=3\times CH_3=C_3H_9

Thus molecular formula will be C_3H_9

6 0
3 years ago
_______ properties depend on the concentration of a solute in a solution but not on the identity of the solute.
Grace [21]

This problem is providing us with a statement in which we need to figure out the word fitting in the blank. At the end, after analyzing the information, the word turns out to be colligative as show below:

<h3>Colligative properties.</h3>

In chemistry, colligative properties of solutions account for the behavior of a solution with respect to the pure solvent, to which a solute is added.

Among them, we have boiling point elevation, freezing point depression, vapor pressure lowering and osmotic pressure, which are all affected by the concentration of the solute but not by the identity of the solute.

In such a way, we conclude that the correct word that fits in the blank is colligative as shown below:

"Colligative properties depend on the concentration of a solute in a solution but not on the identity of the solute."

Learn more about colligative properties: brainly.com/question/10323760

5 0
2 years ago
A student used 1.2 g of hydrate in the first trial and 1.6 g in the second trial. Explain fully why her mass percent of water wi
Pachacha [2.7K]

Both trials of 1.2 g and 1.6 g will have the same mass percent of water because the ratio of the salt to the water of hydration is always constant for any hydrated salt.

<h3>Water of hydration</h3>

For every hydrated salt, the ratio of the salt to the water of hydration remains constant irrespective of the amount of salt taken for experimental analysis.

For example, assuming the mass percent of water in 10g of a hydrated salt is 40%, if 100g of the same salt is taken, the mass percent will remain 40%.

More on water of hydration can be found here: brainly.com/question/11202174

8 0
2 years ago
I need help please .!
Debora [2.8K]

hydrogen (H2),and oxygen (O2),, that is the answer





8 0
4 years ago
PLS HELP ME ON MY FINAL MULTIPLE CHOICE
dexar [7]

Answer:

The force would decrease

5 0
3 years ago
Read 2 more answers
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