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4 years ago

If m = 45g and V = 15ml, what is D in g/ml?

Chemistry

1 answer:

ch4aika [34]4 years ago

6 0

Answer:

3 g/mL

Explanation:

We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).

Formula

D=m/v

Given data:

Mass= 45 g

Volume= 15 mL

Now we will put the values in formula:

D=45 g/ 15 mL= 3 g/mL

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An aqueous solution of calcium hydroxide is standardized by titration with a 0.120 M solution of hydrobromic acid. If 16.5 mL of

Artist 52 [7]

<u>Answer:</u> The molarity of calcium hydroxide in the solution is 0.1 M

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HBr$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.120M\\V_1=27.5mL\\n_2=2\\M_2=?M\\V_2=16.5mL$

Putting values in above equation, we get:

$1\times 0.120\times 27.5=2\times M_2\times 16.5\\\\M_2=0.1M$

Hence, the molarity of $Ca(OH)_2$ in the solution is 0.1 M.

7 0

3 years ago

Can someone plzzz help me with this numbers 1-13 plzz show work plzzz due tomorrow I need help I’ll give brainliest

ipn [44]

Explanation:

Question 1:

We have to use the aid of the periodic table to solve this problem and decipher some of the species.

The number of protons is the number of positively charged particles. It the same as the atomic number.

Number of electrons is the number of negatively charged particles.

Neutrons do not carry any charges.

Mass number = number of protons + number of neutrons

Solving:

Symbol #atomic #protons #electrons #neutrons mass# atomic mass

Fe 26 26 26 30 56 55.8

As³⁺ 33 33 36 42 75 74.9

Ag 47 47 47 61 108 107.9

I¹⁻ 53 53 54 74 127 126.9

K 19 19 19 20 39 39.1

learn more:

Atomic number brainly.com/question/2057656

Question 2:

An ion is an atom that has either lost or gained electron.

A positively charged ion is one that has lost electrons and the number of protons is now more. They are called cation

A negatively charged specie is one that has gained electrons and the number of electrons are now more. They are called anions.

Mass number is the superscript = Number of protons + number of neutrons

Atomic number = number of protons = number of electrons for neutral atoms

Species:

₇¹⁴N³⁻

Number of protons = 7

Number of electrons = 7 + charge = 7+ 3 = 10

Number of neutrons = 14 - 7 = 7

¹¹²₄₈Cd²⁺

Number of protons = 48

Number of electrons = 48 -2 = 46

Number of neutrons = 112 - 48 = 64

⁶⁴₂₉Cu

Number of protons = 29

Number of electrons = 29

Number of neutrons = 64 - 29 = 35

¹¹⁹₄₄Sn⁴⁺

Number of protons = 44

Number of electrons = 44 - 4 = 40

Number of neutrons = 119 - 44 = 75

¹⁹₉F⁻

Number of protons = 9

Number of electrons = 9+ 1 = 10

Number of neutrons = 19 - 9 = 10

learn more:

Number of protons, neutrons and electrons brainly.com/question/2757829

Question 3:

Mass number

The number 79 in Se - 79 specifies the mass number of the element. It suggests that Se is the number 34 element on the periodic table.

The periodic table arranges elements based on their atomic number.
The atomic number is the number of protons in an atom
Every atoms has a unique atomic number which makes them different from other atoms.
In neutral atoms, the atomic number is the same as the number of protons and the number of electrons in an atom.
The mass number is the number of protons plus neutrons of an atom.

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Mass of proton brainly.com/question/4999318

Question 4:

Number of protons = 14

Atomic structure:

²⁸₁₄Si

In this atom designated above Si is the symbol of Silicon, the fourteenth element in the periodic table.
The superscript 28 is the mass number of the atom
The mass number is the number of protons and neutrons in the nucleus of the atom.
It is also called the nucleon number because protons and neutrons are nucleons.
The subscript 14 is the atomic number.
It is the number of protons in the atom.
For neutral atoms, it is also the number of electrons

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Number of protons, neutrons and electrons brainly.com/question/2757829

Question 5:

The total number of subatomic particles = 289

Structure is ²⁰⁷₈₂Pb

The subatomic particles in an atom are protons, neutrons and electrons
Protons are the positively charged particles in an atom
Neutrons have no charge
Electrons carry negative charges

In the atom above, since it is neutral, the number of protons = number of electrons

Number of protons = atomic number

This is the subscript;

Number of protons = 82

Number of electrons = 82

Number of neutrons = mass number - atomic number

Mass number is the superscript

Number of neutrons = 207 - 82 = 125

The total number of subatomic particles = number of protons + number of neutrons + number of electrons

Total number of subatomic particles = 82 + 82 + 125 = 289

learn more:

protons, neutrons and electrons brainly.com/question/2757829

Question 6:

Given parameters :

Number of neutrons = 31

Mass number = 59

Unknown:

Atomic number = ?

Solution:

The mass number of an atom is the number of protons and neutrons it contains.

The mass of an atom is concentrated in the nucleus and this is where we derive the mass number from;

Mass number = number of protons + number of neutrons

Number of protons = 59 - 31 = 28

The number of protons in an atom is the same as the atomic number.

Atomic number = 28

learn more:

Atomic number brainly.com/question/2057656

Question 13 remainder;

When sodium loses an electron, the number of protons will be more than that of electrons

It then becomes an ion;

Number of protons = 11

Number of electrons = 11 - 1 = 10 Charge = 11 - 10 = 1+

With a loss of one electron, sodium will now resemble Ne more closely because it has a stable configuration.

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7 0

3 years ago

Answer the in under 30 minutes and I will give brainliest

gtnhenbr [62]

Answer: I believe the answer is an earthquake.

Explanation: Sorry If I am wrong!

8 0

3 years ago

Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to

Bess [88]

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density $\rho_{avg}$ ; we have:

$\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$

The average atomic weight is:

$A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$

So; in terms of vanadium, the Concentration of iron is:

$C_{Fe} = 100 - C_v$

From a unit cell volume $V_c$

$V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}$

where;

$N_A$ = number of Avogadro constant.

SO; replacing $V_c$ with $a^3$ ; $\rho_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$ ; $A_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$ and

$C_{Fe}$ with $100-C_v$

Then:

$a^3 = \dfrac { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) } {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big) }$

Replacing the values; we have:

$(0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol) } }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3) } }$

$2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} } \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }$