Answer:
2.7 x 10^-19 J
Explanation:
The formula needed for this problem is
E = hν
where E = energy, h = Planck's constant = 6.626x10^-34 and ν is the frequency
c = λν
where c = speed of light = 3x10^8, and λ = wavelength
3x10^8 = 7.35x10^-7 . ν
ν = 4.08 x 10^14 Hz
E = 6.626x10^-34 . 4.08x10^14 = 2.7 x 10^-19 J
Answer: d-orbitals account for the sulphur- oxygen double bond.
Explanation:
Looking at the nature of bonding in SOCl2, the sulphur is bonded to two chlorine atoms and one oxygen atom. The sulphur has a lone pair of electrons. There are four bonds and four electron pairs if we don't count the lone pair on sulphur. This leads to a tetrahedral shape. However, if we invoke a valence state in which d orbitals are involved and the thionyl chloride is still sp3 hybridized, then we will have one electron in the d-orbital which overlaps with a 2p electron from oxygen to form the double bond. The four sp3 orbitals accommodate eight electrons including the lone pair on sulphur while the d-orbital accommodates the remaining two electrons from the pi-bond thereby completing the ten electrons. The approach of canonical structures and charge separation shown in the image attached
Answer:
We have to add 14 mL of water to dilute the alcohol solution from 13% to 6%
Explanation:
Step 1: Data given
Original solution has 12 mL of 13% alcohol
New volume has a concentration of 6%
Step 2: Determine how much pure alcohol you have in the solution.
0.13 * 12ml = 1.56 ml pure alcohol.
Step 3: Calculate ratio alcohol: total in volume
1.56 ml / 12 ml = .013
Step 4: add water to the total solution and set the desired percentage
1.56 ml / (12ml + x) = 0.06
1.56 = 0.06 (12 + x)
1.56 = 0.72 + 0.06x
0.84 = 0.06x
x = 14
We have to add 14 mL of water to dilute the alcohol solution from 13% to 6%
Answer:
the second option is correct
Explanation:
maybe I think b is correct