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I'm going to assume that you mean't mole instead of mile. One mole of O2 has approximately the same mass of one "mole" of N2. I say this because if these elements were rounded by their atomic mass, N would stay as 14, O would round up to 16, and we wouldn't; in this case, O2 would have approximately the same mass as F because F rounds up to 19 and the different between O and N is only 2 while the difference between O and F is 3.
Answer:
747mL of the 0.157mL are needed
Explanation:
To find the grams of salt we need to convert these grams to moles using molar mass of magnesium nitrate (148.3g/mol). Then, with the molar concentration we can convert the moles to liters and, as last, to milliliters, as follows:
<em>Moles Mg(NO₃)₂:</em>
17.4g * (1mol / 148.3g) = 0.117 moles of magnesium nitrate
<em>Volume:</em>
0.117 moles * (1L / 0.157moles) = 0.747L
= 747mL of the 0.157mL are needed
<em>In a 0.157M solution there are 0.157 moles per liter of solution</em>
Answer:
The answer to the question is letter a. 2
Explanation:
Write the formula of each compound
Calcium hydroxide = Ca(OH)₂
Nitric acid = HNO₃
Water = H₂O
Calcium nitrate = Ca(NO₃)₂
Chemical Reaction
Ca(OH)₂ + HNO₃ ⇒ Ca(NO₃)₂ + H₂O
Reactants Elements Products
1 Ca 1
1 N 2
3 H 2
5 O 7
Balanced Chemical Reaction
Ca(OH)₂ + 2HNO₃ ⇒ Ca(NO₃)₂ + 2H₂O
Reactants Elements Products
1 Ca 1
2 N 2
4 H 4
8 O 8
