12. A las 10 de la mañana Elena sale a 100 Km/h de una ciudad A con dirección a Madrid. A la misma hora sale Javier desde otra c
1 answer:
Answer:
a) t = 3.3 [h]
b ) Hora = 13:18 o 1:18 [pm]
c) x = 327.79 [km/h] (Elena)
x = 196.6 [km] (Javier)
Explanation:
Para poder solucionar este problema debemos hacer un planteamiento inicial de ubicacion de las ciudades, este planteamiento nos ayudara a entender el problema de una manera mas facil.
Tenemos las ciudades A & B y la ciudad de Madrid que esta a una distancia x con respecto de B, (ver esquema adjunto).
De manera logica debemos deducir que la Ciudad A debe estar mas lejos de Madrid que la ciudad B de la misma Madrid, ya que en caso contrario Javier nunca alcanzara a Elena, ya que Elena va mas rapido que Javier.
a) Ahora debemos de utilizar la siguiene ecuacion de la cinematica, cuando los cuerpos se mueven a velocidad constante.
Donde:
x -xo = Distancia entre el punto inicial y punto final.
v = velocidad [m/s]
t = tiempo [s]
Debemos convertir las velocidades de kilometros por hora a metros por segundo.
Seguidamente formulamos una ecuacion por cada movimiento, luego debemos igualar estas ecuaciones en funcion de la variable x que sera el punto donde se encuentren ambas personas.
<u>Para Elena</u>
<u>Para Javier</u>
<u /><u />
Igualamos las variables x de ambas ecuaciones.
b) La hora facilmente se puede encontrar sumando el tiempo con las 10:00am
hora = 10 + 3 = 13 [hrs]
La parte decimal debe convertirse a tiempo.
Hora = 13:18 o 1:18 [pm]
c) Para encontrar estas distancias utilizamos el tiempo encontrado en el item a.
<u>Para Elena</u>
<u>Para Javier</u>
<u /><u />
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