Answer:
D All
Explanation:
Mechanical and electromagnetic waves both carry energy. The mechanical wave via the motion/vibration of particles, and the electromagnetic via vibration of the electric and magnetic fields.
We know of interference patterns of light (electromagnetic interference), as well as interference of mechanical waves of water generating typical patterns.
Both, electromagnetic and mechanical waves go through the process of reflection when hitting a barrier (mirror for example in the case of light, and a solid wall for example in the case of water waves.
So the correct answer is "All of the above"
Answer:
17 N
Explanation:
Constant velocity means acceleration is 0.
If acceleration is 0, then the net force is 0. Which means the i components add up to 0, the j components add up to 0, and the k components add up to 0.
0 = 2.0 N − 8.0 N + Fi
Fi = 6.0 N
0 = 4.0 N + 9.0 N + Fj
Fj = -13 N
0 = -2.0 N − 8.0 N + Fk
Fk = 10. N
The magnitude of the force is:
F² = Fi² + Fj² + Fk²
F² = (6.0 N)² + (-13 N)² + (10. N)²
F = √305 N
F ≈ 17 N
Answer:
120 deg Unknown = 100 deg Celsius since we know that the ice point is at
0 deg Celsius and the steam point is 100 deg Celsius
So you have 1.2 deg U / 1 deg C
70 deg U / (1.2 deg U / 1 deg c) = 58.3 deg C (temperature in deg Celsius)
Or 58.3deg C * 1.2 deg U / 1 deg C = 70 deg U
Answer:
v = 91.8 Km / h
Explanation:
We must start this exercise at the end, let's look for the lighter car acceleration (B), for this we use Newton's second law
fr = m a
a = fr / m
fr = μ N
N-W = 0
Let's replace
a = μ m g / m
a = μ g
a = 0.8 9.8
a = 7.84 m / s²
As the car B after the crash reached an initial velocity vo₀₂ and at the end of the fine speed zero, let us use kinematics
v² = v₀₂² - 2 a x
0 = v₀₂² - 2 a x
v₀₂ = 2 a x₂
v₀₂ = √ (2 7.84 26)
v₀₂ = 20.19 m / s
Let's perform the same procedure for car A, the acceleration is the same as it does not depend on the mass of the vehicles
v₀₁ = √ 2 a x₁
v₀₁ = √ (2 7.84 19)
v₀₂ = 17.36 m / s
Now let's use moment conservation, where the system is the two vehicles
Initial before crash.
p₀ = M v₁ + 0
After the crash
= M v₀₁ + m v₀₂
p₀ =
M v₁ = M v₀₁ + m v₀₂
v₁ = v₀₁ + m / M v₀₂
v₁ = 17.36 + 1841/3000 20.19
v₁ = 20.75 m / s
This is the speed of car 1 (A) just before the crash, now let's look for the speed when I apply the brakes the initial speed (v)
v₁² = v² - 2 a x₁
v = √ (v₁² + 2 a x₁)
v = √ (20.75² + 2 7.84 14)
v = 25.50 m / s
v = 25.50 m / s (1km / 1000m) (3600s / 1h)
v = 91.8 Km / h