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Angelina_Jolie [31]
3 years ago
9

How much heat is required to heat 5.25 g of water h2o from 5.5?

Chemistry
1 answer:
Evgen [1.6K]3 years ago
5 0
Heat = mass * heat capacity of water * change in temperature mass = 5.25 g heat capacity of water = 4.186 joule/gram °C Change in temperature = 62.8°C - 5.3°C = 57.5 °C Plug in the values heat = 5.25 g * 4.186 joule/gram °C * 57.5 °C = 1263.6 J Rounded to two three significant figures, it is 1260 J of energy needed. In terms of calories, the heat capacity of water is 1 calorie/gram °C. So do the plugging in all over again. mass = 5.25 g heat capacity of water = 1 calorie/gram °C Change in temperature = 62.8°C - 5.3°C = 57.5 °C heat = 5.25 g * 1 calorie/gram °C * 57.5 °C = 301.9 calories Rounded to 3 significant figures, it is 302 calories Q=SM∆T=4.18*5.25*(62.8-4.3)=1280 J 1280 J * (1 cal/4.18 J) = 307 cal
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To whoever helps me thank you so much have a wonderful day!
Schach [20]

Answer:

N and P

Explanation:

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In given problem N and phosphorus both can gain three electrons which means negative charge becomes greater that's why the extra electron gained by atoms are written as -3 and both form anion with charge -3.

while Al form cation with charge +3 Mg form cation with charge +2 and iodine and bromine both form anion with charge of -1.

8 0
3 years ago
An atom has 2 protons in its nucleus . Which of the following must be true for this atom to have no net electrical charge
ehidna [41]
If an atom has 2 protons, then it must also have 2 electrons for there to be no charge. An extra electron will cause for you to have a negative charge, and if you have more protons than electrons, then you will have a positive charge. :)
7 0
3 years ago
Which equation represents positron decay?
jonny [76]

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8 0
2 years ago
At what temperature, would the volume of a gas
PtichkaEL [24]

Explanation:

P1V1 = nRT1

P2V2 = nRT2

Divide one by the other:

P1V1/P2V2 = nRT1/nRT2

From which:

P1V1/P2V2 = T1/T2

(Or P1V1 = P2V2 under isothermal conditions)

Inverting and isolating T2 (final temp)

(P2V2/P1V1)T1 = T2 (Temp in K).

Now P1/P2 = 1

V1/V2 = 1/2

T1 = 273 K, the initial temp.

Therefore, inserting these values into above:

2 x 273 K = T2 = 546 K, or 273 C.

Thus, increasing the temperature to 273 C from 0C doubles its volume, assuming ideal gas behaviour. This result could have been inferred from the fact that the the volume vs temperature line above the boiling temperature of the gas would theoretically have passed through the origin (0 K) which means that a doubling of temperature at any temperature above the bp of the gas, doubles the volume.

From the ideal gas equation:

V = nRT/P or at constant pressure:

V = kT where the constant k = nR/P. Therefore, theoretically, at 0 K the volume is zero. Of course, in practice that would not happen since a very small percentage of the volume would be taken up by the solidified gas.

8 0
3 years ago
A patient needs to take 875mg twice daily The pills in the bottle are each 250mg How many pills does she wants to take 875mg
Angelina_Jolie [31]

Answer:

3.5 pill need to taken for completing dosage of 875 mg

Explanation:

Total dosage of medicine to be taken in a day

= 2 * 875 \\= 1750mg

Total weight of one pill = 250 mg

Number of pills required is equal to total dosage of medicine divided by the weight of one pill.

Hence,

Number of pills

= \frac{875}{250} \\= \frac{175}{50} \\= \frac{35}{10} \\= 3.5

6 0
3 years ago
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