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lions [1.4K]
3 years ago
6

How do movements and interactions of air masses cause change in the weather?

Chemistry
1 answer:
ollegr [7]3 years ago
5 0
The way the air moves affects the weather, because winds move heat and cold temperatures as well as moisture from one place to another, transporting conditions from one geographical zone to another. The way winds pass each other, and the direction they move, also affects what weather a region will see on any given day.
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Scoring Scheme: 3-3-2-1 Part I. How many mL of 6 M NaOH stock solution should be used to prepare the 500 mL of 0.2 M NaOH? Pleas
Orlov [11]

Answer : The volume of 6M NaOH stock solution is, 16.7 mL

Explanation :

To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of NaOH stock solution.

M_2\text{ and }V_2 are the molarity and volume of NaOH.

We are given:

M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL

Putting values in above equation, we get:

6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL

Thus, the volume of 6M NaOH stock solution is, 16.7 mL

4 0
4 years ago
I need to know how to find atoms on a periodic table.
Juli2301 [7.4K]

Answer:

you get atoms number left down the element example hydrogen has 1 atoms number and mass number.

7 0
3 years ago
How is a light bulb related to radiation?
ElenaW [278]

Answer:

As light is emitted from the filament, the energy in the metal is replaced as lightbulbs absorb background radiation. This prevents the filament from burning out quickly but the radiation cannot be used as power so electricity is still required for the lightbulb to work.

5 0
3 years ago
Water freezes at 32 degrees
olga55 [171]

Answer:

Fahrenheit

Explanation:

7 0
3 years ago
Read 2 more answers
2FeCl3 + 3Mg → 3MgCl2 + 2Fe
kondaur [170]

Answer:

\large \boxed{\text{A. 3.0 mol}}

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

               2FeCl₃ + 3Mg ⟶ 3MgCl₂ + 2Fe

n/mol:                     4.5

2 mol of FeCl₃ react with 3 mol of Mg

\text{Moles of FeCl}_{3}  = \text{4.5 mol Mg}\times \dfrac{\text{2 mol FeCl}_{3}}{\text{3 mol Mg}}= \textbf{3.0 mol Mg}\\\\\text{The reaction will need $\large \boxed{\textbf{3.0 mol of Mg}}$}

4 0
3 years ago
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