Question

A 250mL beaker is submerged in a large container of Liquid A and turned upside down, and another 250mL beaker is submerged and turned upside down in a large container of Liquid B. Hydrogen H2 gas is bubbled into each upside-down beaker until 100mL of liquid has been displaced. The masses mA and mB of hydrogen inside each beaker is then chemically determined. Note for advanced students: you may assume the solubility of H2 in either liquid is very low.
a. mx will be greater than my
b. mx will be less than my
c. mx will be equal to my
d. It's impossible to predict whether mx or my will be greater without more information.

Answer 1

Answer:

Mx will be less than My.

Explanation:

The correct option is - Mx will be less than My.

Because, liquid X have been higher viscosity and vapor pressure than liquid B.

Vapor pressure of liquid A is greater, so the amount of liquid X will vaporized greater and H2 gas has been displaced greater from the beaker as compared to liquid Y.

The amount of H2 in liquid Y remains greater in beaker as compared to liquid X.

So, Mx will be less than My.