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svlad2 [7]
3 years ago
14

An optically active alkyne A (C10H14) can be catalytically hydrogenated to butylcyclohexane. Treatment of A with C2H5MgBr libera

tes no gas. Catalytic hydrogenation of A over Pd/C in the presence of quinoline poison and treatment of the product B with O3 and then H2O2 gives an optically active tricarboxylic acid C8H12O6. (A tricarboxylic acid is a compound with three –CO2H groups.) Give the structure of A (without stereochemistry).
Chemistry
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

The reverse process, hydrogenation, can be performed in the presence of a catalyst like metallic platinum. Hydrogen gas reacts with the metal surface, breaking the hydrogen-hydrogen bond to form weaker metal-hydrogen bonds. An alkene or alkyne can then react with the metal in a similar manner, then form stronger bonds with two or more hydrogen

Explanation:

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Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with
skad [1K]

A.  Decomposing water requires a high activation energy.

Explanation:

In decomposing water to release hydrogen gas to make fuel cells, the process requires a very high activation energy.

                             2H₂O ⇆ 2H₂  + O₂

 This is the overall reaction. O-H must be broken to release free hydrogen to produce hydrogen gas.

The O-H bond is a very strong force of attraction that requires a high activation energy to overcome.

  • The activation energy is the energy barrier that must be overcome before a reaction takes place.
  • The sun is a renewable source of energy.
  • Water decomposition produces useful oxygen gas needed by all life for cellular respiration.

Learn more:

Source of energy brainly.com/question/2948717

#learnwithBrainly

4 0
3 years ago
Strontium crystallizes in a face-centered cubic unit cell having an edge length of 77.43 pm. What is the atomic radius of stront
kiruha [24]

Answer:

Atomic radius of Strontium is 27.38pm

Explanation:

In a face-centered cubic structure, the edge, a, could be obtained using pythagoras theorem knowing the hypotenuse of the unit cell, b, is equal to 4r:

a² + a² = b² = (4r)²

2a² = 16r²

a = √8 r

As edge length of Strontium is 77.43pm:

77.43pm / √8 = r

27.38pm = r

<h3>Atomic radius of Strontium is 27.38pm</h3>

5 0
3 years ago
What is the change in density if a sample goes from 3.21 g/L to 5.43 g/mL?
Step2247 [10]

Answer:

\Delta \rho =2.22 g/mL

Explanation:

Hello,

In this case, since a change in science is widely known to be considered as a subtraction between the the final and initial values of two measured variables and is represented via Δ, here the final density is 5.43 g/mL and the initial one was 3.21 g/mL, therefore, the change in density is:

\Delta \rho=\rho _f-\rho _i\\ \\\Delta \rho=5.43g/mL-3.21g/mL\\\\\Delta \rho =2.22 g/mL

Best regards.

3 0
3 years ago
Soil horizons develop as a result of
harkovskaia [24]
The interactions of climate, living organisms, and landscape .
4 0
3 years ago
Read 2 more answers
What is required on a chemical label
Pani-rosa [81]

Answer: What is required on a chemical label includes pictograms, a signal word, hazard and precautionary statements, the product identifier, and supplier identification.

Explanation:

4 0
4 years ago
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