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svlad2 [7]
3 years ago
14

An optically active alkyne A (C10H14) can be catalytically hydrogenated to butylcyclohexane. Treatment of A with C2H5MgBr libera

tes no gas. Catalytic hydrogenation of A over Pd/C in the presence of quinoline poison and treatment of the product B with O3 and then H2O2 gives an optically active tricarboxylic acid C8H12O6. (A tricarboxylic acid is a compound with three –CO2H groups.) Give the structure of A (without stereochemistry).
Chemistry
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

The reverse process, hydrogenation, can be performed in the presence of a catalyst like metallic platinum. Hydrogen gas reacts with the metal surface, breaking the hydrogen-hydrogen bond to form weaker metal-hydrogen bonds. An alkene or alkyne can then react with the metal in a similar manner, then form stronger bonds with two or more hydrogen

Explanation:

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Alcohol, alcohol is the only liquid  since copper and aluminum are a solid ammonia is a bacteria
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True or False When the attraction between the particles overcomes their motion the particles clump together to boil. ​
bixtya [17]

Answer:

False

Explanation:

It is wrong to claim that when the attraction between particles overcomes their motion, the particles will clump together to boil.

During boiling particles do no clump together, they tend to move apart more rapidly.

  • Boiling occurs when the vapor pressure overcomes the ambient atmospheric pressure.
  • The hotter part of the boiler close the heat source moves rapidly away because they have become less dense.
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6 0
3 years ago
What conclusion can you make about a hypothesis that contradicts an existing theory?
Naddika [18.5K]
What are you making a hypothesis for 
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3 years ago
if a gas sample in a balloon occupies 1.5 L at atmospheric pressure, what would be the pressure (in mmHg) if the volume was redu
Nata [24]

Answer:

1425 mmHg.

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 1.5 L

Initial pressure (P1) = 1 atm

Final volume (V2) = 0.8 L

Final pressure (P2) =?

Next, we shall determine the final pressure of the gas by using the Boyle's law equation as follow:

P1V1 = P2V2

1 × 1.5 = P2 × 0.8

1.5 = P2 × 0.8

Divide both side by 0.8

P2 = 1.5/0.8

P2 = 1.875 atm

Finally, we shall convert 1.875 atm to mmHg.

This can be obtained as follow:

1 atm = 760 mmHg

Therefore,

1.875 atm = 1.875 × 760 = 1425 mmHg.

Therefore, the new pressure of the gas is 1425 mmHg.

3 0
3 years ago
If the distance between a point charge and a neutral atom and is multiplied by a factor of 5, by what factor does the force on t
dexar [7]

Given :

The distance between a point charge and a neutral atom and is multiplied by a factor of 5.

To Find :

By what factor does the force on the neutral atom by the point charge change.

Solution :

We know, electrostatic force between two object is directly proportional to product of charge and inversely proportional to distance between them.

Now, charge in neutral atom is 0 C.

So, the electrostatic force between two of them is also 0 N.

Therefore, by changing distance between the charge the forces did no change ( it remains zero).

3 0
3 years ago
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