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Elena L [17]
3 years ago
7

Decribe what must happen inside of an aluminum can in order for it to be attracted to a positively-charged and to a negatively-c

harged object
Physics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

The PROTONS in the can attract to the negatively charged object, so then the can becomes polarized and the ELECTRONS in the can attract the positively charged object.

Explanation:

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Which major planet has the largest . . . A. semimajor axis? B. average orbital speed around the Sun? C. orbital period around th
Yuliya22 [10]
<h2>Mercury, Neptune, and Jupiter </h2>

Explanation:

  • Mercury has the largest semimajor axis that is 5.791 x 107 in km.
  • Mercury is the planet with the fastest speed, which has an average orbital speed around the sun for about 47.87 km/s.
  • Neptune has the longest orbital speed around the sun of any planet in the Solar System which is equivalent to 164.8 years (or 60,182 Earth days)
  • Jupiter has the largest eccentricity.

Hence, the answer is Mercury, Neptune, and Jupiter respectively.

6 0
3 years ago
Two balls, one twice as massive as the other, are dropped from the roof of a building (freefall). Just before hitting the ground
Katena32 [7]

KE= 1/2 mv^2

Kinetic Energy is equal to 1/2 x mass x velocity squared

The mass of the larger ball has TWICE
the kinetic energy. KE is directly proportional to the mass.

6 0
3 years ago
A 26-kg sled is on a snow-covered slope. The coefficients of friction between the sled’s runners and the snow are µs = 0.096 and µ
sweet-ann [11.9K]

Answer:

Explanation:

Given

mass of sled =26 kg

coefficient of static friction \mu _s=0.096

coefficient of kinetic friction \mu _k=0.072

In order to move sled from rest we need to provide a force greater than static friction which is given by

f_s=\mu mg=0.096\times 26\times 9.8=24.46 N

After Moving Sled kinetic friction comes in to play which is less than static friction

f_k=\mu _kmg=0.072\times 26\times 9.8=18.34 N

therefore minimum force to keep moving sledge at constant velocity is 18.34 N

3 0
3 years ago
A physical count of merchandise inventory on november 30
Zigmanuir [339]
It depends on the indirect taxes and the share market values
4 0
3 years ago
The force F1, 10.0N acts at 10.0cm. What is the magnitude of the torque due to F1 about an axis through Point A perpendicular to
Nookie1986 [14]
Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution. Feel free to ask more question. 

<span>torque = rF
= 0.1(10)
=1 Nm</span>
4 0
3 years ago
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