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3 years ago

Rachel is placing playing cards on a table by following these steps.

1 answer:

meriva3 years ago

7 0

Rachel is placing playing cards on a table by following these steps.
Step 1: First she places one card in the middle of the table.
Step 2: Next she adds one more card directly to the left, to the right, and below the first card.
Step 3: Next she adds one more card directly to the left, to the right, above, and below the cards that were already on the table. The cards form the pattern shown.

a. If Rachel continues the same pattern, how many cards will be on the table after Rachel completes Step 4?
b. Write the first 6 terms of the sequence that represents the total number of cards on the table after each step.
c. Describe the pattern in the sequence.

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What is the solution to the equation -4x-12=-11x+23

Hitman42 [59]

-4x-(-12)=(-11x)+23
+12 +12
-4x=(-11x)+35
+11x +11x
7x=35
/7 /7
x=5

6 0

3 years ago

Help meh plz i am begging you

igor_vitrenko [27]

full question not given...please resend

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3 years ago

Find the sin in the triangle

Ierofanga [76]

Answer:

.324 or 18.9 degrees

Step-by-step explanation:

rule is

sine equals opposite over hypotenuse,

cosine equals adjacent over hypotenuse, and

tangent equals opposite over adjacent

soh cah toa

sine = soh = 12/37 = .324

arcsin(.324) or sin^-1(.324) in DEGREES not radians =

18.9 degrees

6 0

3 years ago

Please help me with these. These are so hard.<br><br>

LuckyWell [14K]

$\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}$

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0

3 years ago

What is the answer for | 3x - 2 | = 8 and | x + 1 | = 1

Umnica [9.8K]

X = -2

3 x -2 = -6
-6 -2= -8
|-8| = 8

-2 + 1= -1
|-1|=1

8 0

3 years ago