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Fantom [35]
3 years ago
11

Supongo que quiere preparar una solución al 10% de sulfato de magnesio en peso. El frasco del producto químico que se tiene indi

ca que el sulfato de magnesio heptahidratado Cuántos gramos de hidratado serán necesarios para preparar 120 gramos de esta solución .Cuántos gramos de agua?
Chemistry
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

Se requerirán 14.57 gramos de MgSO₄·7H₂O, que se disolverían en 105.43 gramos de agua.

Explanation:

Si tenemos 120 gramos de una solución al 10% de sulfato de magnesio en peso, habrán en la solución (120*10/100) 12 gramos de sulfato de magnesio (MgSO₄).

Sin embargo, el reactivo que está disponible es heptahidratado (MgSO₄·7H₂O), por lo que hay que calcular <em>cuántos gramos de sulfato de magnesio heptahidratado contendrán 12 gramos de MgSO₄</em>.

<u>Calculamos las moles de 12 gramos de MgSO₄</u>, usando su masa molecular:

  • 12 g MgSO₄ ÷ 120.305 g/mol = 0.0997 mol MgSO₄.

<u>Después calculamos la masa de MgSO₄·7H₂O que contendrá 0.0997 mol MgSO₄</u>, usando la masa molecular de MgSO₄·7H₂O:

  • 0.0997 mol * 246.305 g/mol = 14.57 g MgSO₄·7H₂O

Para saber la cantidad de agua en la que se disolverá el reactivo, restamos la masa de soluto de la masa total de la solución:

  • 120 g - 14.57 g = 105.43 g

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D. volcano, fissure :)
4 0
2 years ago
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Which methods would be suitable for determining the concentration of an aqueous solution of KMnO4? I. Visible spectrophotometry
Elodia [21]

Answer:

C

Explanation:

Since the solution have an observable color, that means that it absorbs light in the visible region hence it can be determined by colorimetry. Secondly, KMnO4 is a reducing agent which can be titrated against an oxidizing agent and it's concentration accurately determined.

3 0
3 years ago
If the caffeine concentration in a particular brand of soda is 3.55 mg/oz, drinking how many cans of soda would be lethal? Assum
monitta

Answer:

The answer to your question is: 234.7 cans

Explanation:

data

caffeine concentration = 3.55 mg/oz

10.0 g of caffeine is lethal

there are 12 oz of caffeine in a can

Then

                    3.55 mg ----------------- 1 oz

                      x    mg  -----------------12 oz (in a can)

x = 42.6 mg of caffeine in a can

Convert it to grams 42,6 mg = 0.0426 g of caffeine in a can

Finally

            0.0426 g of caffeine ------------------  1 can

            10           g of caffeine -----------------    x

x = 10 x 1/0.0436 = 234.7 cans

6 0
3 years ago
The speed of Train A is 88 km/hr, and the speed of Train B is 96 km/hr. Based on this information, which of the following statem
denis-greek [22]

Answer:

C i took that test and got 96

Explanation:

7 0
2 years ago
The specific heat of gold is 0.031 calories/gram°C. If 10.0 grams of gold were heated and the temperature of the sample
IgorLugansk [536]

Answer:

6.2 calories

Explanation:

Data Given:

change in temperature = 20 °C

specific heat of gold = 0.031 calories/gram °C

mass of gold = 10.0 grams

Amount of Heat = ?

Solution:

Formula used

             Q = Cs.m.ΔT

Where:

Q = amount of heat

Cs = specific heat of gold = 0.031 calories/gram °C

m = mass

ΔT = Change in temperature

Put values in above equation

                Q = 0.031 calories/gram °C x 10.0 g x 20 °C

                Q = 6.2 calories

So option A is correct = 6.2 calories

6 0
3 years ago
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