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Fantom [35]
3 years ago
11

Supongo que quiere preparar una solución al 10% de sulfato de magnesio en peso. El frasco del producto químico que se tiene indi

ca que el sulfato de magnesio heptahidratado Cuántos gramos de hidratado serán necesarios para preparar 120 gramos de esta solución .Cuántos gramos de agua?
Chemistry
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

Se requerirán 14.57 gramos de MgSO₄·7H₂O, que se disolverían en 105.43 gramos de agua.

Explanation:

Si tenemos 120 gramos de una solución al 10% de sulfato de magnesio en peso, habrán en la solución (120*10/100) 12 gramos de sulfato de magnesio (MgSO₄).

Sin embargo, el reactivo que está disponible es heptahidratado (MgSO₄·7H₂O), por lo que hay que calcular <em>cuántos gramos de sulfato de magnesio heptahidratado contendrán 12 gramos de MgSO₄</em>.

<u>Calculamos las moles de 12 gramos de MgSO₄</u>, usando su masa molecular:

  • 12 g MgSO₄ ÷ 120.305 g/mol = 0.0997 mol MgSO₄.

<u>Después calculamos la masa de MgSO₄·7H₂O que contendrá 0.0997 mol MgSO₄</u>, usando la masa molecular de MgSO₄·7H₂O:

  • 0.0997 mol * 246.305 g/mol = 14.57 g MgSO₄·7H₂O

Para saber la cantidad de agua en la que se disolverá el reactivo, restamos la masa de soluto de la masa total de la solución:

  • 120 g - 14.57 g = 105.43 g

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