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liraira [26]
3 years ago
13

If A = 3x² + 5x - 6 and B=-2/- 6x + 7, then

Mathematics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

{5x }^{2}  + 11x - 13

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Michelle is working on a design for a new building. She has built a model of the building according to the client's specificatio
Snezhnost [94]

Answer:

Step-by-step explanation:

980

6 0
3 years ago
Find Mx, My, and (x, y) for the lamina of uniform density rho bounded by the graphs of the equations. y = x2/3, y = 0, x = 1
erik [133]

Answer:

\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8},  \dfrac{5}{14})}

Step-by-step explanation:

Given that:

y =  x^{2/3} at y = 0 , x = 1

Then:

Area = \int^{1}_{0} x^{2/3} \ dx

Area = \begin {bmatrix} \dfrac{3}{5}x^{5/3} \end {bmatrix} ^1_0

Area = \dfrac{3}{5}

Then:

\overline x = \dfrac{1}{A} \int^b_a x (f(x) -g(x) ) \ dx

\overline x = \dfrac{5}{3} \int^1_0 x (x^{2/3} -0 ) \ dx

\overline x = \dfrac{5}{3} \int^1_0 x^{5/3} \ dx

\overline x = \dfrac{5}{3} \ [\dfrac{3}{8}x^{8/3}]^1_0

\overline x = \dfrac{5}{3} \times \dfrac{3}{8}

\overline x = \dfrac{5}{8}

Similarly;

\overline y = \dfrac{1}{A} \int^b_a \dfrac{1}{2} \begin{bmatrix} (f(x)^)2 - (g(x))^2 \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (f(x^{2/3})^2 -0 \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (x^{4/3} ) \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{1}{2}  (x^{7/3} ) \times \dfrac{3}{7} \end {bmatrix} ^1_0

\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{3}{14}  (x^{7/3} ) \end {bmatrix} ^1_0

\overline y = (\dfrac{5}{3} \times \dfrac{3}{14} )

\overline y = \dfrac{5}{14}

Thus; \mathbf{(\overline x , \overline y ) = (\dfrac{5}{8},  \dfrac{5}{14})}

4 0
3 years ago
How do you write 1+0.9+0.08+0.001 in standard form
lions [1.4K]
Just addum up.

You should get the sum of  1.981 .
That's in standard form.
6 0
4 years ago
Read 2 more answers
I don't know whats wrong, please help. It is the exact formula.
const2013 [10]
The formula for circumference is 2\pir, where r is equal to radius.
It states to use 3.142 for pi
It also provides you with the diameter, not the radius, so you have to divide it by two to get 4.5
2*3.142*4.5= approximately 28.278 or 28.3
4 0
4 years ago
Read 2 more answers
8.35 &lt; 3x +18.75<br> Pls help
zzz [600]

Step-by-step explanation:

8.35 < 3x + 18.75

3x + 18.75 > 8.35

3x > 8.35 - 18.75

3x > -10.4

x > -3.47

5 0
3 years ago
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