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d1i1m1o1n [39]
3 years ago
15

Pop said, "I have three grandchildren on my knee: Vera, Chuck and Dave. "Chuck is three years younger than Dave.

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
8 0
Okie dokie buddy pokie
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THIS IS SO HARD ILL CROWN U BRANLIEST IF U GET IT CORRECT
Leni [432]

Answer:

Its B

Step-by-step explanation:

My classmate told me and I got it right

7 0
3 years ago
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
James has a mass of 32.8 kg. Ricardo's mass is 8 3/4 kg more than James's. Winthorp's mass is 3.6 kg less than Ricardo's. What i
strojnjashka [21]

Answer:79.5

Step-by-step explanation:32.8+8.75=41.55 41.55-3.6=37.95 37.95+41.55+32.8=79.5

3 0
3 years ago
Regular pentagon<br><br> sides 3.3 cm long
OleMash [197]
3.3 x 5 = 16.5 cm
Happy to Help!
7 0
3 years ago
Please help!! 15 Points!!!!
Ray Of Light [21]

Answer:

I think it is ether A are B

3 0
3 years ago
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