All categories

3 years ago

Question 11

1 answer:

4 0

It depends on the graphics, color, structure all that stuff for me to believe if the image is real or virtual
Hope I helped you

You might be interested in

Explian the construction of electric motor?

Nataly_w [17]

Answer:

Hope the above picture might help you :)

7 0

3 years ago

An electron is projected with an initial speed of 5 3.2 10 / ⋅ m s directly toward a proton that is fixed in place. If the elect

Dvinal [7]

Answer:

The distance is $d =1.66*10^{-9}m$

Explanation:

From the question we are told that

The initial speed of the electron is $v_i = 3.2 *10^5 m/s$

The mass of electron is $m = 9.11*10^{-31}kg$

Let $d$ be the distance between the electron and the proton when the speed of the electron instantaneously equal to twice the initial value

Let $KE_i$ be the initial kinetic energy of the electron \

Let $KE_d$ be the kinetic energy of the electron at the distance $d$ from the proton

Considering that energy is conserved,

The energy at the initial position of the electron = The energy at the final position of the electron

i.e

$KE_i +U_1 = KE_d + U_2$

$U_1 \ and \ U_2$ are the potential energy at the initial position of the electron and at distance d of the electron to the proton

Here $U_1 = 0$

So the equation becomes

$\frac{1}{2} mv_i^2 = \frac{1}{2} mv_d^2 + \frac{kq_1 q_2}{d}$

Here $q_1 \ and \ q_2$ are the charge on the electron and the proton and their are the same since a charge on an electron is equal to charge on a proton

$k$ is electrostatic constant with value $8.99*10^9 N \cdot m^2 /C^2$

i.e $q = 1.602 *10^{-19}C$

$v_d$ is the velocity at distance d from the proton = 2 $v_i$

So the equation becomes

$\frac{1}{2}mv_i^2 = \frac{1}{2} m (2v_i)^2 -\frac{k(q)^2}{d}$

$\frac{1}{2} mv_i^2 = 4 [\frac{1}{2}mv_i^2 ]- \frac{k(q)^2}{d}$

$3[\frac{1}{2}mv_i^2 ] = \frac{k(q)^2}{d}$

Making d the subject of the formula

$d = \frac{2k(q)^2}{3mv_i^2}$

$= \frac{2* 8.99*10^9 *(1.602*10^{-19}^2)}{3 * 9.11*10^{-31} *(3.2*10^5)^2}$

$=1.66*10^{-9}m$

6 0

3 years ago

GO TO MY LATEST QUESTION AND ANSWER <br> I WILL BRAINLIST AND GIVE 35 POINTS TO THE CORRECT ANSWER

REY [17]

y e s s s s i r r r r r r

8 0

3 years ago

Are these combination of resistors in series or parallel?

34kurt

These resistors are in series.
Think of it of where the electrons can travel in the system. If there are multiple options for where they can travel then it is parallel, if there are no split paths (only one option) then it is series.

An example of a combination of resistors in parallel: The image you have above, but replace R2 with a wire that continues to the right to a battery. Then resistors R1 and R3 are in parallel.

7 0

3 years ago

How high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside?

pashok25 [27]

Answer:

15 m

Explanation:

Given,

Mass ( m ) = 75 kg

Potential energy ( P.E ) = 11,025 J

To find : Hight ( h )

Formula : -

P.E = mgh

[ Note : The value of g = 9.8 m/s² ]

h = P.E / mg

= 11,025 / ( 75 x 9.8 )

= 11,025 / 735

h = 15 m

Hence,

15 m is the high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside.

3 0

2 years ago