Answer:
absorb , it absorbs it ...
Answer:
a) v(2) = 2m/s, v(3) = -2m/s
b) speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
c) 0 m/s
Explanation:
We can take the derivative of x(t) to find the equation of velocity
v(t) = x'(t) = 10 - 4t
(a) v(2) = 10 - 4*2 = 10 - 8 = 2 m/s
v(3) = 10 - 4*3 = 10 - 12 = -2 m/s
(b) The speed would be the same as velocity without the direction
speed at t = 2s is 2m/s
speed at t = 3s is 2m/s
(c) The average velocity between t = 2s and t = 3s is distance it travels over period of time
Answer:
The velocity of the one thrown up will be the same as the second one
Explanation:
They will fall and hit the ground at the same time although they have the same velocity because object one although has double height it has initial velocity of zero
This is a beautiful problem to test whether a student actually understands
Newton's 2nd law of motion . . . Force = (mass) x (acceleration).
That simple law is all you need to solve this problem, but you need to
use it a few times.
m₁ alone:
Force = (mass) x (acceleration)
36 N = ( m₁ ) x (6 m/s²)
m₁ = (36 N) / (6 m/s²)
m₁ = 6 kilograms .
m₁ and m₂ glued together:
Force = (mass) x (acceleration)
36 N = (6 kg + m₂) x (2 m/s²)
6 kg + m₂ = (36 N) / (2 m/s²) = 18 kilograms
m₂ = 12 kilograms .
m₂ alone:
Force = (mass) x (acceleration)
36 N = (12 kg) x (acceleration)
Acceleration = (36 N) / (12 kg)
Acceleration = 3 m/s²
