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Katyanochek1 [597]
3 years ago
9

The symbol Ca-40 denotes that

Chemistry
1 answer:
Roman55 [17]3 years ago
8 0
D. A calcium atom has mass of 40
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scoundrel [369]
Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 1 O d) 2
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2 years ago
What is the second most abundant element in stars? A. helium B. iron C. hydrogen D. oxygen
devlian [24]
<span>The </span>abundance of a chemical element<span> is a measure of the </span>occurrence<span> of the </span>element<span> relative to all other elements in a given environment. Abundance is measured in one of three ways: by the </span>mass-fraction<span> (the same as weight fraction); by the </span>mole-fraction<span> (fraction of atoms by numerical count, or sometimes fraction of molecules in gases); or by the </span>volume-fraction<span>. Volume-fraction is a common abundance measure in mixed gases such as planetary atmospheres, and is similar in value to molecular mole-fraction for gas mixtures at relatively low densities and pressures, and </span>ideal gas<span> mixtures. Most abundance values in this article are given as mass-fractions.

</span>
8 0
3 years ago
If two substances travel up the chromatography paper this implies that
Colt1911 [192]

Answer:

They are seperating

Explanation:

6 0
2 years ago
What is the molality of a solution if 100.0 g of glucose (C&amp;Hi20e) were dissolved into 750. mL of water?
hodyreva [135]

<u>Answer:</u> The molality of solution is 0.740 m.

<u>Explanation:</u>

To calculate the mass of solvent (water), we use the equation:

Density=\frac{Mass}{Volume}

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g

To calculate the molality of solution, we use the equation:

Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (C_6H_{12}O_6) = 100.0 g

M_{solute} = Molar mass of solute (C_6H_{12}O_6) = 180 g/mol

W_{solvent} = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m

Hence, the molality of solution is 0.740 m.

6 0
3 years ago
Given the noble gas configuration of an element: [Ar] 4s2, 3d5, what is the element?
monitta

Question

<em>Given the noble gas configuration of an element: [Ar] 4s2, 3d5, what is the element? </em>

Answer:

<em>B.) Argon</em>

Hope this helps!

6 0
3 years ago
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