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Katyanochek1 [597]
3 years ago
9

The symbol Ca-40 denotes that

Chemistry
1 answer:
Roman55 [17]3 years ago
8 0
D. A calcium atom has mass of 40
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When 35.0 mL of 0.400 M hydrobromic acid and 35.0 mL of 0.400 M ammonia are combined, the pH of the resulting solution will be :
Kay [80]

Answer:

B. Equal to 7.

Explanation:

Hydrobromic acid is a strong acid that decreases pH and ammonia is a strong base that increases pH.

As the initial pH of water is 7,0 the addition of 35.0mL of 0.400M HBr will produce a pH less than 7,0. But, the same effect of decreasing pH is reverted for the addition of 35.0mL of 0.400M HNO3.

That means the net effect of the two addition is to have a pH:

B. Equal to 7.

I hope it helps!

3 0
2 years ago
What three compounds are produced by the combustion of hydrocarbon fuels?
MakcuM [25]
The most common hydrogen carbon fuels are ethanol and diesel and their product of combustion is carbon dioxide, water and heat . 


8 0
2 years ago
Please help on this question
natulia [17]
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But I will tell u the system of the Hadley cells---
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a large-scale atmospheric convection cell in which air rises at the equator and sinks at medium latitudes, typically about 30° north or south.
7 0
3 years ago
Which opinion would be an example of an alloy <br> brass or <br> silver or <br> gold or <br> copper
frutty [35]

Answer:

Gold and copper are example of alloy

Explanation:

8 0
2 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Alinara [238K]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
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