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3 years ago

Is baking soda an acid, base, or neutral

Chemistry

1 answer:

sergey [27]3 years ago

6 0

Answer:

Baking soda is an alkaline, or base, substance. This means that when we dissolve baking soda in water, it forms an alkaline solution. For example, a 0.1 molar solution of baking soda has a pH of around 8.3. Lemon juice contains citric acid and has a pH of around 3.

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Jerod used a golf club to hit a ball what was the action and reaction

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The action was him hitting the ball the reaction was the ball moving after being hit

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3 years ago

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Explain what it means to be considered a “renewable” energy source, and what it means to be a “non-renewable” energy source.

Neporo4naja [7]

Answer: Resources are characterized as renewable or nonrenewable

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3 years ago

Which of the following is used to show sound waves?

Ipatiy [6.2K]

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3 years ago

A buffer solution is composed of 1.00 mol of acid and 2.25 mol of the conjugate base. If the p K a of the acid is 4.90 , what is

Gemiola [76]

<u>Answer:</u> The pH of the buffer is 5.25

<u>Explanation:</u>

Let the volume of buffer solution be V

We know that:

$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution}}$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{conjugate base}]}{[acid]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of weak acid = 4.90

$[\text{conjugate base}]=\frac{2.25}{V}$

$[acid]=\frac{1.00}{V}$

pH = ?

Putting values in above equation, we get:

$pH=4.90+\log(\frac{2.25/V}{1.00/V})\\\\pH=5.25$

Hence, the pH of the buffer is 5.25

4 0

3 years ago

Your apple juice has a molarity of 3.4 M and a volume of 0.895 litres. What does a student have to do to decrease the molarity t

Jlenok [28]

Answer:

4.285 L of water must be added.

Explanation:

Hello there!

In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:

$M_1V_1=M_2V_2\\\\V_2=\frac{M_1V_1}{M_2}$

Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:

$V_2=\frac{3.4M*0.895 L}{0.587M}\\\\V_2=5.18L$

It means we need to add:

$V_{H_2O} ^{added}=5.18L-0.895L=4.285L$

Of diluent water.

Regards!

6 0

3 years ago